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A1C worksheet

Grade 9 · CCSS HSA.CED.A.4

Solve each problem and show your work. Round answers to 2 decimal places where needed.

1.
Problem 1.
- I know my: Average glucose (find A1C)
- Average blood glucose: 90 mg/dL
Find: Matching A1C
Answer
2.
Problem 2.
- I know my: Average glucose (find A1C)
- Average blood glucose: 212 mg/dL
Find: Matching A1C
Answer
3.
Problem 3.
- I know my: Average glucose (find A1C)
- Average blood glucose: 117 mg/dL
Find: Matching A1C
Answer
4.
Problem 4.
- I know my: Average glucose (find A1C)
- Average blood glucose: 170 mg/dL
Find: Matching A1C
Answer
5.
Problem 5.
- I know my: A1C (find average glucose)
- A1C result: 12%
Find: Estimated average glucose (eAG)
Answer
6.
Problem 6.
- I know my: A1C (find average glucose)
- A1C result: 7%
Find: Estimated average glucose (eAG)
Answer
7.
Problem 7.
- I know my: A1C (find average glucose)
- A1C result: 6.8%
Find: Estimated average glucose (eAG)
Answer
8.
Problem 8.
- I know my: A1C (find average glucose)
- A1C result: 5.7%
Find: Estimated average glucose (eAG)
Answer
9.
Problem 9.
- I know my: A1C (find average glucose)
- A1C result: 5.4%
Find: Estimated average glucose (eAG)
Answer
10.
Problem 10.
- I know my: A1C (find average glucose)
- A1C result: 9%
Find: Estimated average glucose (eAG)
Answer

Answer key: A1C worksheet

1. Matching A1C: 4.8 %
1. Run the A1C formula backward: add 46.7 to the average glucose, then divide by 28.7
  $\frac{(90 + 46.7)}{28.7}$ $= 4.7631 %$
2. Change A1C from percent to mmol/mol, the unit many labs outside the US use: subtract 2.152, then divide by 0.09148
  $\frac{(4.7631 - 2.152)}{0.09148}$ $= 28.54 mmol/mol$
2. Matching A1C: 9 %
1. Run the A1C formula backward: add 46.7 to the average glucose, then divide by 28.7
  $\frac{(212 + 46.7)}{28.7}$ $= 9.0139 %$
2. Change A1C from percent to mmol/mol, the unit many labs outside the US use: subtract 2.152, then divide by 0.09148
  $\frac{(9.0139 - 2.152)}{0.09148}$ $= 75.01 mmol/mol$
3. Matching A1C: 5.7 %
1. Run the A1C formula backward: add 46.7 to the average glucose, then divide by 28.7
  $\frac{(117 + 46.7)}{28.7}$ $= 5.7038 %$
2. Change A1C from percent to mmol/mol, the unit many labs outside the US use: subtract 2.152, then divide by 0.09148
  $\frac{(5.7038 - 2.152)}{0.09148}$ $= 38.83 mmol/mol$
4. Matching A1C: 7.6 %
1. Run the A1C formula backward: add 46.7 to the average glucose, then divide by 28.7
  $\frac{(170 + 46.7)}{28.7}$ $= 7.5505 %$
2. Change A1C from percent to mmol/mol, the unit many labs outside the US use: subtract 2.152, then divide by 0.09148
  $\frac{(7.5505 - 2.152)}{0.09148}$ $= 59.01 mmol/mol$
5. Estimated average glucose (eAG): 298 mg/dL
1. Use the ADAG formula: multiply the A1C percent by 28.7, then subtract 46.7. That gives average glucose in mg/dL
  $28.7 \times 12 - 46.7$ $= 297.7 mg/dL$
2. Change mg/dL to mmol/L by dividing by 18.0156, the mg/dL in 1 mmol/L of glucose
  $\frac{297.7 mg/dL}{18.0156}$ $= 16.525 mmol/L$
3. Change A1C from percent to mmol/mol, the unit many labs outside the US use: subtract 2.152, then divide by 0.09148
  $\frac{(12 - 2.152)}{0.09148}$ $= 107.65 mmol/mol$
6. Estimated average glucose (eAG): 154 mg/dL
1. Use the ADAG formula: multiply the A1C percent by 28.7, then subtract 46.7. That gives average glucose in mg/dL
  $28.7 \times 7 - 46.7$ $= 154.2 mg/dL$
2. Change mg/dL to mmol/L by dividing by 18.0156, the mg/dL in 1 mmol/L of glucose
  $\frac{154.2 mg/dL}{18.0156}$ $= 8.559 mmol/L$
3. Change A1C from percent to mmol/mol, the unit many labs outside the US use: subtract 2.152, then divide by 0.09148
  $\frac{(7 - 2.152)}{0.09148}$ $= 53 mmol/mol$
7. Estimated average glucose (eAG): 148 mg/dL
1. Use the ADAG formula: multiply the A1C percent by 28.7, then subtract 46.7. That gives average glucose in mg/dL
  $28.7 \times 6.8 - 46.7$ $= 148.46 mg/dL$
2. Change mg/dL to mmol/L by dividing by 18.0156, the mg/dL in 1 mmol/L of glucose
  $\frac{148.46 mg/dL}{18.0156}$ $= 8.241 mmol/L$
3. Change A1C from percent to mmol/mol, the unit many labs outside the US use: subtract 2.152, then divide by 0.09148
  $\frac{(6.8 - 2.152)}{0.09148}$ $= 50.81 mmol/mol$
8. Estimated average glucose (eAG): 117 mg/dL
1. Use the ADAG formula: multiply the A1C percent by 28.7, then subtract 46.7. That gives average glucose in mg/dL
  $28.7 \times 5.7 - 46.7$ $= 116.89 mg/dL$
2. Change mg/dL to mmol/L by dividing by 18.0156, the mg/dL in 1 mmol/L of glucose
  $\frac{116.89 mg/dL}{18.0156}$ $= 6.488 mmol/L$
3. Change A1C from percent to mmol/mol, the unit many labs outside the US use: subtract 2.152, then divide by 0.09148
  $\frac{(5.7 - 2.152)}{0.09148}$ $= 38.78 mmol/mol$
9. Estimated average glucose (eAG): 108 mg/dL
1. Use the ADAG formula: multiply the A1C percent by 28.7, then subtract 46.7. That gives average glucose in mg/dL
  $28.7 \times 5.4 - 46.7$ $= 108.28 mg/dL$
2. Change mg/dL to mmol/L by dividing by 18.0156, the mg/dL in 1 mmol/L of glucose
  $\frac{108.28 mg/dL}{18.0156}$ $= 6.01 mmol/L$
3. Change A1C from percent to mmol/mol, the unit many labs outside the US use: subtract 2.152, then divide by 0.09148
  $\frac{(5.4 - 2.152)}{0.09148}$ $= 35.51 mmol/mol$
10. Estimated average glucose (eAG): 212 mg/dL
1. Use the ADAG formula: multiply the A1C percent by 28.7, then subtract 46.7. That gives average glucose in mg/dL
  $28.7 \times 9 - 46.7$ $= 211.6 mg/dL$
2. Change mg/dL to mmol/L by dividing by 18.0156, the mg/dL in 1 mmol/L of glucose
  $\frac{211.6 mg/dL}{18.0156}$ $= 11.745 mmol/L$
3. Change A1C from percent to mmol/mol, the unit many labs outside the US use: subtract 2.152, then divide by 0.09148
  $\frac{(9 - 2.152)}{0.09148}$ $= 74.86 mmol/mol$