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Aspect Ratio worksheet

Grades 6–7 · CCSS 6.RP.A.3.a

Solve each problem and show your work. Round answers to 2 decimal places where needed.

1.
Problem 1.
- Calculation: Find a missing width or height
- Aspect ratio: 16:9 (HD and 4K video, most TVs)
- I know the: Height
- Known side: 1,600
Find: Width
Answer
2.
Problem 2.
- Calculation: Find a missing width or height
- Aspect ratio: 21:9 (ultrawide, nominal)
- I know the: Height
- Known side: 1,100
Find: Width
Answer
3.
Problem 3.
- Calculation: Find the ratio of a width and height
- Width: 1,400
- Height: 980
Find: Aspect ratio (simplest form)
Answer
4.
Problem 4.
- Calculation: Find the ratio of a width and height
- Width: 2,100
- Height: 1,275
Find: Aspect ratio (simplest form)
Answer
5.
Problem 5.
- Calculation: Find a missing width or height
- Aspect ratio: 21:9 (ultrawide, nominal)
- I know the: Height
- Known side: 1,525
Find: Width
Answer
6.
Problem 6.
- Calculation: Find the ratio of a width and height
- Width: 1,500
- Height: 880
Find: Aspect ratio (simplest form)
Answer
7.
Problem 7.
- Calculation: Find a missing width or height
- Aspect ratio: 9:16 (vertical phone video)
- I know the: Width
- Known side: 1,600
Find: Height
Answer
8.
Problem 8.
- Calculation: Find a missing width or height
- Aspect ratio: Custom ratio
- Ratio width (W in W:H): 7
- Ratio height (H in W:H): 3
- I know the: Height
- Known side: 1,800
Find: Width
Answer
9.
Problem 9.
- Calculation: Find the ratio of a width and height
- Width: 2,000
- Height: 775
Find: Aspect ratio (simplest form)
Answer
10.
Problem 10.
- Calculation: Find the ratio of a width and height
- Width: 1,800
- Height: 900
Find: Aspect ratio (simplest form)
Answer

Answer key: Aspect Ratio worksheet

1. Width: 2,844.44
1. Keeping the ratio fixed means width ÷ height must equal W ÷ H
  $\frac{width}{height}$ $= \frac{16}{9}$ $= 1.777778$
2. Solve for the width: multiply the known height by W, then divide by H
  $width$ $= \frac{1,600 \times 16}{9}$ $= 2,844.444444$
3. For pixels, round to the nearest whole pixel; the ratio then shifts very slightly
  $2,844.444444$ $= 2,844$
2. Width: 2,566.67
1. Keeping the ratio fixed means width ÷ height must equal W ÷ H
  $\frac{width}{height}$ $= \frac{21}{9}$ $= 2.333333$
2. Solve for the width: multiply the known height by W, then divide by H
  $width$ $= \frac{1,100 \times 21}{9}$ $= 2,566.666667$
3. For pixels, round to the nearest whole pixel; the ratio then shifts very slightly
  $2,566.666667$ $= 2,567$
3. Aspect ratio (simplest form): 10:7
1. Find the greatest common divisor (GCD), the largest whole number that divides both sides
  $GCD (1,400, 980)$ $= 140$
2. Divide both sides by 140 to get the simplest ratio
  $\frac{1,400}{140} : \frac{980}{140}$ $= 10:7$
3. Divide width by height for the decimal form, which makes different ratios easy to compare
  $\frac{1,400}{980}$ $= 1.428571$
4. Aspect ratio (simplest form): 28:17
1. Find the greatest common divisor (GCD), the largest whole number that divides both sides
  $GCD (2,100, 1,275)$ $= 75$
2. Divide both sides by 75 to get the simplest ratio
  $\frac{2,100}{75} : \frac{1,275}{75}$ $= 28:17$
3. Divide width by height for the decimal form, which makes different ratios easy to compare
  $\frac{2,100}{1,275}$ $= 1.647059$
5. Width: 3,558.33
1. Keeping the ratio fixed means width ÷ height must equal W ÷ H
  $\frac{width}{height}$ $= \frac{21}{9}$ $= 2.333333$
2. Solve for the width: multiply the known height by W, then divide by H
  $width$ $= \frac{1,525 \times 21}{9}$ $= 3,558.333333$
3. For pixels, round to the nearest whole pixel; the ratio then shifts very slightly
  $3,558.333333$ $= 3,558$
6. Aspect ratio (simplest form): 75:44
1. Find the greatest common divisor (GCD), the largest whole number that divides both sides
  $GCD (1,500, 880)$ $= 20$
2. Divide both sides by 20 to get the simplest ratio
  $\frac{1,500}{20} : \frac{880}{20}$ $= 75:44$
3. Divide width by height for the decimal form, which makes different ratios easy to compare
  $\frac{1,500}{880}$ $= 1.704545$
7. Height: 2,844.44
1. Keeping the ratio fixed means width ÷ height must equal W ÷ H
  $\frac{width}{height}$ $= \frac{9}{16}$ $= 0.5625$
2. Solve for the height: multiply the known width by H, then divide by W
  $height$ $= \frac{1,600 \times 16}{9}$ $= 2,844.444444$
3. For pixels, round to the nearest whole pixel; the ratio then shifts very slightly
  $2,844.444444$ $= 2,844$
8. Width: 4,200
1. Keeping the ratio fixed means width ÷ height must equal W ÷ H
  $\frac{width}{height}$ $= \frac{7}{3}$ $= 2.333333$
2. Solve for the width: multiply the known height by W, then divide by H
  $width$ $= \frac{1,800 \times 7}{3}$ $= 4,200$
9. Aspect ratio (simplest form): 80:31
1. Find the greatest common divisor (GCD), the largest whole number that divides both sides
  $GCD (2,000, 775)$ $= 25$
2. Divide both sides by 25 to get the simplest ratio
  $\frac{2,000}{25} : \frac{775}{25}$ $= 80:31$
3. Divide width by height for the decimal form, which makes different ratios easy to compare
  $\frac{2,000}{775}$ $= 2.580645$
10. Aspect ratio (simplest form): 2:1
1. Find the greatest common divisor (GCD), the largest whole number that divides both sides
  $GCD (1,800, 900)$ $= 900$
2. Divide both sides by 900 to get the simplest ratio
  $\frac{1,800}{900} : \frac{900}{900}$ $= 2:1$
3. Divide width by height for the decimal form, which makes different ratios easy to compare
  $\frac{1,800}{900}$ $= 2$