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Blood Type Inheritance worksheet

Grades 7–8 · CCSS 7.SP.C.8.b, 7.SP.C.8.a

Solve each problem and show your work. Round answers to 2 decimal places where needed.

1.
Problem 1.
- Parent 1 ABO type: AB
- Parent 1 Rh factor: Positive (+)
- Parent 1 Rh genes, if known: Two positive alleles (DD)
- Parent 2 ABO type: O
- Parent 2 Rh factor: Negative (−)
Find: Possible child blood types
Answer
2.
Problem 2.
- Parent 1 ABO type: B
- Parent 1 Rh factor: Negative (−)
- Parent 1 ABO genes, if known: Carries O (AO or BO)
- Parent 2 ABO type: B
- Parent 2 Rh factor: Negative (−)
- Parent 2 ABO genes, if known: Two copies of the same allele (AA or BB)
Find: Possible child blood types
Answer
3.
Problem 3.
- Parent 1 ABO type: B
- Parent 1 Rh factor: Positive (+)
- Parent 1 ABO genes, if known: Two copies of the same allele (AA or BB)
- Parent 1 Rh genes, if known: Not known (weigh both equally)
- Parent 2 ABO type: A
- Parent 2 Rh factor: Positive (+)
- Parent 2 ABO genes, if known: Not known (weigh both equally)
- Parent 2 Rh genes, if known: Two positive alleles (DD)
Find: Possible child blood types
Answer
4.
Problem 4.
- Parent 1 ABO type: O
- Parent 1 Rh factor: Positive (+)
- Parent 1 Rh genes, if known: Not known (weigh both equally)
- Parent 2 ABO type: A
- Parent 2 Rh factor: Positive (+)
- Parent 2 ABO genes, if known: Two copies of the same allele (AA or BB)
- Parent 2 Rh genes, if known: Carries negative (Dd)
Find: Possible child blood types
Answer
5.
Problem 5.
- Parent 1 ABO type: B
- Parent 1 Rh factor: Positive (+)
- Parent 1 ABO genes, if known: Two copies of the same allele (AA or BB)
- Parent 1 Rh genes, if known: Two positive alleles (DD)
- Parent 2 ABO type: O
- Parent 2 Rh factor: Positive (+)
- Parent 2 Rh genes, if known: Carries negative (Dd)
Find: Possible child blood types
Answer
6.
Problem 6.
- Parent 1 ABO type: B
- Parent 1 Rh factor: Negative (−)
- Parent 1 ABO genes, if known: Carries O (AO or BO)
- Parent 2 ABO type: A
- Parent 2 Rh factor: Negative (−)
- Parent 2 ABO genes, if known: Not known (weigh both equally)
Find: Possible child blood types
Answer
7.
Problem 7.
- Parent 1 ABO type: B
- Parent 1 Rh factor: Positive (+)
- Parent 1 ABO genes, if known: Not known (weigh both equally)
- Parent 1 Rh genes, if known: Not known (weigh both equally)
- Parent 2 ABO type: AB
- Parent 2 Rh factor: Negative (−)
Find: Possible child blood types
Answer
8.
Problem 8.
- Parent 1 ABO type: A
- Parent 1 Rh factor: Positive (+)
- Parent 1 ABO genes, if known: Not known (weigh both equally)
- Parent 1 Rh genes, if known: Two positive alleles (DD)
- Parent 2 ABO type: O
- Parent 2 Rh factor: Positive (+)
- Parent 2 Rh genes, if known: Carries negative (Dd)
Find: Possible child blood types
Answer
9.
Problem 9.
- Parent 1 ABO type: AB
- Parent 1 Rh factor: Positive (+)
- Parent 1 Rh genes, if known: Not known (weigh both equally)
- Parent 2 ABO type: AB
- Parent 2 Rh factor: Negative (−)
Find: Possible child blood types
Answer
10.
Problem 10.
- Parent 1 ABO type: O
- Parent 1 Rh factor: Negative (−)
- Parent 2 ABO type: O
- Parent 2 Rh factor: Negative (−)
Find: Possible child blood types
Answer

Answer key: Blood Type Inheritance worksheet

1. Possible child blood types: A+, B+
1. List the ABO gene pairs (genotypes) each parent could have. A and B are dominant, so they can hide an O
  $Parent 1: AB; Parent 2: OO$
2. Each parent passes on one of their two ABO alleles at random. A Punnett square of every pairing gives the child's ABO chances
  $A 50%, B 50%$
3. Do the same for Rh. One D allele is enough for positive, so Rh+ is DD or Dd and Rh− is dd
  $Parent 1: DD; Parent 2: dd → Rh+ 100%$
4. The two genes are passed on separately, so multiply the ABO chance by the Rh chance for each type
  $A+ 50%, B+ 50%$
5. Possible blood types for a child
  $A+, B+$
2. Possible child blood types: B−
1. List the ABO gene pairs (genotypes) each parent could have. A and B are dominant, so they can hide an O
  $Parent 1: BO; Parent 2: BB$
2. Each parent passes on one of their two ABO alleles at random. A Punnett square of every pairing gives the child's ABO chances
  $B 100%$
3. Do the same for Rh. One D allele is enough for positive, so Rh+ is DD or Dd and Rh− is dd
  $Parent 1: dd; Parent 2: dd → Rh− 100%$
4. The two genes are passed on separately, so multiply the ABO chance by the Rh chance for each type
  $B− 100%$
5. Possible blood types for a child
  $B−$
3. Possible child blood types: B+, AB+
1. List the ABO gene pairs (genotypes) each parent could have. A and B are dominant, so they can hide an O
  $Parent 1: BB; Parent 2: AA 50% or AO 50%$
2. Each parent passes on one of their two ABO alleles at random. A Punnett square of every pairing gives the child's ABO chances
  $B 25%, AB 75%$
3. Do the same for Rh. One D allele is enough for positive, so Rh+ is DD or Dd and Rh− is dd
  $Parent 1: DD 50% or Dd 50%; Parent 2: DD → Rh+ 100%$
4. The two genes are passed on separately, so multiply the ABO chance by the Rh chance for each type
  $B+ 25%, AB+ 75%$
5. Possible blood types for a child
  $B+, AB+$
4. Possible child blood types: A+, A−
1. List the ABO gene pairs (genotypes) each parent could have. A and B are dominant, so they can hide an O
  $Parent 1: OO; Parent 2: AA$
2. Each parent passes on one of their two ABO alleles at random. A Punnett square of every pairing gives the child's ABO chances
  $A 100%$
3. Do the same for Rh. One D allele is enough for positive, so Rh+ is DD or Dd and Rh− is dd
  $Parent 1: DD 50% or Dd 50%; Parent 2: Dd → Rh+ 87.5%, Rh− 12.5%$
4. The two genes are passed on separately, so multiply the ABO chance by the Rh chance for each type
  $A+ 87.5%, A− 12.5%$
5. Possible blood types for a child
  $A+, A−$
5. Possible child blood types: B+
1. List the ABO gene pairs (genotypes) each parent could have. A and B are dominant, so they can hide an O
  $Parent 1: BB; Parent 2: OO$
2. Each parent passes on one of their two ABO alleles at random. A Punnett square of every pairing gives the child's ABO chances
  $B 100%$
3. Do the same for Rh. One D allele is enough for positive, so Rh+ is DD or Dd and Rh− is dd
  $Parent 1: DD; Parent 2: Dd → Rh+ 100%$
4. The two genes are passed on separately, so multiply the ABO chance by the Rh chance for each type
  $B+ 100%$
5. Possible blood types for a child
  $B+$
6. Possible child blood types: A−, B−, AB−, O−
1. List the ABO gene pairs (genotypes) each parent could have. A and B are dominant, so they can hide an O
  $Parent 1: BO; Parent 2: AA 50% or AO 50%$
2. Each parent passes on one of their two ABO alleles at random. A Punnett square of every pairing gives the child's ABO chances
  $A 37.5%, B 12.5%, AB 37.5%, O 12.5%$
3. Do the same for Rh. One D allele is enough for positive, so Rh+ is DD or Dd and Rh− is dd
  $Parent 1: dd; Parent 2: dd → Rh− 100%$
4. The two genes are passed on separately, so multiply the ABO chance by the Rh chance for each type
  $A− 37.5%, B− 12.5%, AB− 37.5%, O− 12.5%$
5. Possible blood types for a child
  $A−, B−, AB−, O−$
7. Possible child blood types: A+, A−, B+, B−, AB+, AB−
1. List the ABO gene pairs (genotypes) each parent could have. A and B are dominant, so they can hide an O
  $Parent 1: BB 50% or BO 50%; Parent 2: AB$
2. Each parent passes on one of their two ABO alleles at random. A Punnett square of every pairing gives the child's ABO chances
  $A 12.5%, B 50%, AB 37.5%$
3. Do the same for Rh. One D allele is enough for positive, so Rh+ is DD or Dd and Rh− is dd
  $Parent 1: DD 50% or Dd 50%; Parent 2: dd → Rh+ 75%, Rh− 25%$
4. The two genes are passed on separately, so multiply the ABO chance by the Rh chance for each type
  $A+ 9.38%, A− 3.13%, B+ 37.5%, B− 12.5%, AB+ 28.13%, AB− 9.38%$
5. Possible blood types for a child
  $A+, A−, B+, B−, AB+, AB−$
8. Possible child blood types: A+, O+
1. List the ABO gene pairs (genotypes) each parent could have. A and B are dominant, so they can hide an O
  $Parent 1: AA 50% or AO 50%; Parent 2: OO$
2. Each parent passes on one of their two ABO alleles at random. A Punnett square of every pairing gives the child's ABO chances
  $A 75%, O 25%$
3. Do the same for Rh. One D allele is enough for positive, so Rh+ is DD or Dd and Rh− is dd
  $Parent 1: DD; Parent 2: Dd → Rh+ 100%$
4. The two genes are passed on separately, so multiply the ABO chance by the Rh chance for each type
  $A+ 75%, O+ 25%$
5. Possible blood types for a child
  $A+, O+$
9. Possible child blood types: A+, A−, B+, B−, AB+, AB−
1. List the ABO gene pairs (genotypes) each parent could have. A and B are dominant, so they can hide an O
  $Parent 1: AB; Parent 2: AB$
2. Each parent passes on one of their two ABO alleles at random. A Punnett square of every pairing gives the child's ABO chances
  $A 25%, B 25%, AB 50%$
3. Do the same for Rh. One D allele is enough for positive, so Rh+ is DD or Dd and Rh− is dd
  $Parent 1: DD 50% or Dd 50%; Parent 2: dd → Rh+ 75%, Rh− 25%$
4. The two genes are passed on separately, so multiply the ABO chance by the Rh chance for each type
  $A+ 18.75%, A− 6.25%, B+ 18.75%, B− 6.25%, AB+ 37.5%, AB− 12.5%$
5. Possible blood types for a child
  $A+, A−, B+, B−, AB+, AB−$
10. Possible child blood types: O−
1. List the ABO gene pairs (genotypes) each parent could have. A and B are dominant, so they can hide an O
  $Parent 1: OO; Parent 2: OO$
2. Each parent passes on one of their two ABO alleles at random. A Punnett square of every pairing gives the child's ABO chances
  $O 100%$
3. Do the same for Rh. One D allele is enough for positive, so Rh+ is DD or Dd and Rh− is dd
  $Parent 1: dd; Parent 2: dd → Rh− 100%$
4. The two genes are passed on separately, so multiply the ABO chance by the Rh chance for each type
  $O− 100%$
5. Possible blood types for a child
  $O−$