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Boyle's Law worksheet

Grades 10–11 · CCSS HSA.CED.A.4

Solve each problem and show your work. Round answers to 2 decimal places where needed.

1.
Problem 1.
- Solve for: Initial pressure (P₁)
- Pressure unit (both pressures): Pascals (Pa)
- Volume unit (both volumes): Cubic centimeters (cm³)
- Initial volume (V₁): 13
- Final pressure (P₂): 3
- Final volume (V₂): 3
Find: Initial pressure (P₁)
Answer
2.
Problem 2.
- Solve for: Final pressure (P₂)
- Pressure unit (both pressures): Bars (bar)
- Volume unit (both volumes): Liters (L)
- Initial pressure (P₁): 1
- Initial volume (V₁): 9
- Final volume (V₂): 4
Find: Final pressure (P₂)
Answer
3.
Problem 3.
- Solve for: Initial volume (V₁)
- Pressure unit (both pressures): Hectopascals / millibars (hPa)
- Volume unit (both volumes): Cubic inches (in³)
- Initial pressure (P₁): 2
- Final pressure (P₂): 2
- Final volume (V₂): 4
Find: Initial volume (V₁)
Answer
4.
Problem 4.
- Solve for: Final pressure (P₂)
- Pressure unit (both pressures): Kilopascals (kPa)
- Volume unit (both volumes): Liters (L)
- Initial pressure (P₁): 1
- Initial volume (V₁): 10
- Final volume (V₂): 6
Find: Final pressure (P₂)
Answer
5.
Problem 5.
- Solve for: Initial volume (V₁)
- Pressure unit (both pressures): Torr (Torr)
- Volume unit (both volumes): Liters (L)
- Initial pressure (P₁): 1
- Final pressure (P₂): 3
- Final volume (V₂): 4
Find: Initial volume (V₁)
Answer
6.
Problem 6.
- Solve for: Final pressure (P₂)
- Pressure unit (both pressures): Megapascals (MPa)
- Volume unit (both volumes): Liters (L)
- Initial pressure (P₁): 1
- Initial volume (V₁): 10
- Final volume (V₂): 3
Find: Final pressure (P₂)
Answer
7.
Problem 7.
- Solve for: Final volume (V₂)
- Pressure unit (both pressures): Hectopascals / millibars (hPa)
- Volume unit (both volumes): Cubic feet (ft³)
- Initial pressure (P₁): 1
- Initial volume (V₁): 8
- Final pressure (P₂): 2
Find: Final volume (V₂)
Answer
8.
Problem 8.
- Solve for: Initial volume (V₁)
- Pressure unit (both pressures): Kilopascals (kPa)
- Volume unit (both volumes): US gallons (US gal)
- Initial pressure (P₁): 1
- Final pressure (P₂): 2
- Final volume (V₂): 4
Find: Initial volume (V₁)
Answer
9.
Problem 9.
- Solve for: Initial volume (V₁)
- Pressure unit (both pressures): Millimeters of mercury (mmHg)
- Volume unit (both volumes): Milliliters (mL)
- Initial pressure (P₁): 1
- Final pressure (P₂): 2
- Final volume (V₂): 5
Find: Initial volume (V₁)
Answer
10.
Problem 10.
- Solve for: Final volume (V₂)
- Pressure unit (both pressures): Megapascals (MPa)
- Volume unit (both volumes): Milliliters (mL)
- Initial pressure (P₁): 2
- Initial volume (V₁): 6
- Final pressure (P₂): 2
Find: Final volume (V₂)
Answer

Answer key: Boyle's Law worksheet

1. Initial pressure (P₁): 0.69 Pa
1. Pressure × volume stays the same for this gas, so work it out from the final state, where you know both
  $3 Pa \times 3 cm³$ $= 9 Pa·cm³$
2. Divide that product by the starting volume to get the missing pressure
  $\frac{9}{13 cm³}$ $= 0.6923076923 Pa$
2. Final pressure (P₂): 2.25 bar
1. Pressure × volume stays the same for this gas, so work it out from the starting state, where you know both
  $1 bar \times 9 L$ $= 9 bar·L$
2. Divide that product by the final volume to get the missing pressure
  $\frac{9}{4 L}$ $= 2.25 bar$
3. Initial volume (V₁): 4 in³
1. Pressure × volume stays the same for this gas, so work it out from the final state, where you know both
  $2 hPa \times 4 in³$ $= 8 hPa·in³$
2. Divide that product by the starting pressure to get the missing volume
  $\frac{8}{2 hPa}$ $= 4 in³$
4. Final pressure (P₂): 1.67 kPa
1. Pressure × volume stays the same for this gas, so work it out from the starting state, where you know both
  $1 kPa \times 10 L$ $= 10 kPa·L$
2. Divide that product by the final volume to get the missing pressure
  $\frac{10}{6 L}$ $= 1.6666666667 kPa$
5. Initial volume (V₁): 12 L
1. Pressure × volume stays the same for this gas, so work it out from the final state, where you know both
  $3 Torr \times 4 L$ $= 12 Torr·L$
2. Divide that product by the starting pressure to get the missing volume
  $\frac{12}{1 Torr}$ $= 12 L$
6. Final pressure (P₂): 3.33 MPa
1. Pressure × volume stays the same for this gas, so work it out from the starting state, where you know both
  $1 MPa \times 10 L$ $= 10 MPa·L$
2. Divide that product by the final volume to get the missing pressure
  $\frac{10}{3 L}$ $= 3.3333333333 MPa$
7. Final volume (V₂): 4 ft³
1. Pressure × volume stays the same for this gas, so work it out from the starting state, where you know both
  $1 hPa \times 8 ft³$ $= 8 hPa·ft³$
2. Divide that product by the final pressure to get the missing volume
  $\frac{8}{2 hPa}$ $= 4 ft³$
8. Initial volume (V₁): 8 US gal
1. Pressure × volume stays the same for this gas, so work it out from the final state, where you know both
  $2 kPa \times 4 US gal$ $= 8 kPa·US gal$
2. Divide that product by the starting pressure to get the missing volume
  $\frac{8}{1 kPa}$ $= 8 US gal$
9. Initial volume (V₁): 10 mL
1. Pressure × volume stays the same for this gas, so work it out from the final state, where you know both
  $2 mmHg \times 5 mL$ $= 10 mmHg·mL$
2. Divide that product by the starting pressure to get the missing volume
  $\frac{10}{1 mmHg}$ $= 10 mL$
10. Final volume (V₂): 6 mL
1. Pressure × volume stays the same for this gas, so work it out from the starting state, where you know both
  $2 MPa \times 6 mL$ $= 12 MPa·mL$
2. Divide that product by the final pressure to get the missing volume
  $\frac{12}{2 MPa}$ $= 6 mL$