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Conduit Bending worksheet

Grades 9–10 · CCSS HSG.SRT.C.8

Solve each problem and show your work. Round answers to 2 decimal places where needed.

1.
Problem 1.
- Bend: Back-to-back 90
- Distance between the backs of the two 90s: 42 in
- Bender: 1/2 in EMT bender (5 in take-up)
Find: Mark from the back of the first 90 (star)
Answer
2.
Problem 2.
- Bend: Back-to-back 90
- Distance between the backs of the two 90s: 34 in
- Bender: 1 in EMT bender (8 in take-up)
Find: Mark from the back of the first 90 (star)
Answer
3.
Problem 3.
- Bend: Offset
- Offset depth: 3 in
- Bend angle: 30°
- Distance from the conduit end to the obstacle: 26 in
Find: Distance between bend marks
Answer
4.
Problem 4.
- Bend: 3-point saddle
- Height of the obstacle: 1.5 in
- Distance from the conduit end to the obstacle's center: 26 in
- Center bend: 45° center, 22.5° sides
Find: Center mark from the end
Answer
5.
Problem 5.
- Bend: 90° stub-up
- Stub-up height: 13 in
- Bender: 1/2 in EMT bender (5 in take-up)
Find: Mark from the end of the conduit
Answer
6.
Problem 6.
- Bend: Back-to-back 90
- Distance between the backs of the two 90s: 36 in
- Bender: 3/4 in EMT bender (6 in take-up)
Find: Mark from the back of the first 90 (star)
Answer
7.
Problem 7.
- Bend: Offset
- Offset depth: 5 in
- Bend angle: 22.5°
- Distance from the conduit end to the obstacle: 32 in
Find: Distance between bend marks
Answer
8.
Problem 8.
- Bend: Offset
- Offset depth: 2 in
- Bend angle: 22.5°
- Distance from the conduit end to the obstacle: 40 in
Find: Distance between bend marks
Answer
9.
Problem 9.
- Bend: Back-to-back 90
- Distance between the backs of the two 90s: 35 in
- Bender: Other (enter the take-up)
- Take-up (deduct) of your bender: 6 in
Find: Mark from the back of the first 90 (star)
Answer
10.
Problem 10.
- Bend: 3-point saddle
- Height of the obstacle: 1.5 in
- Distance from the conduit end to the obstacle's center: 34 in
- Center bend: 60° center, 30° sides
Find: Center mark from the end
Answer

Answer key: Conduit Bending worksheet

1. Mark from the back of the first 90 (star): 42 in
1. Star (back-of-bend) method: measure the full distance from the back of the first 90, then bend with the mark on the star
  $mark$ $= 42 in$
2. Arrow method, for short pieces: subtract the take-up, then bend with the bender facing the other way
  $42 - 5$ $= 37 in$
2. Mark from the back of the first 90 (star): 34 in
1. Star (back-of-bend) method: measure the full distance from the back of the first 90, then bend with the mark on the star
  $mark$ $= 34 in$
2. Arrow method, for short pieces: subtract the take-up, then bend with the bender facing the other way
  $34 - 8$ $= 26 in$
3. Distance between bend marks: 6 in
1. Find the multiplier for 30° bends: 1 divided by the sine of the angle. It tells you how far apart the marks go
  $multiplier$ $= \frac{1}{sin 30°}$ $= 2$
2. Multiply the offset depth by the multiplier to get the distance between the two bend marks
  $3 \times 2$ $= 6 in$
3. Work out the shrink, because the slanted section uses up length: depth × tan(30° ÷ 2)
  $3 \times 0.2679$ $= 0.8038 in$
4. Place the first mark (the bend nearest the obstacle): add the shrink to the distance to the obstacle
  $26 + 0.8038$ $= 26.8038 in$
5. Place the second mark by measuring back from the first by the distance between marks
  $26.8038 - 6$ $= 20.8038 in$
4. Center mark from the end: 26.298 in
1. Each side bend is half the 45° center bend. The spacing multiplier is 1 divided by the sine of 22.5°
  $multiplier$ $= \frac{1}{sin 22.5°}$ $= 2.6131$
2. Multiply the obstacle height by the multiplier to get the distance from the center mark to each outer mark
  $1.5 \times 2.6131$ $= 3.9197 in$
3. Work out the shrink, because climbing the obstacle uses up length: height × tan(22.5° ÷ 2)
  $1.5 \times 0.1989$ $= 0.2984 in$
4. Place the center mark: add the shrink to the distance to the obstacle's center
  $26 + 0.2984$ $= 26.2984 in$
5. Measure that spacing out on each side of the center mark for the two outer marks
  $26.2984 - 3.9197 and 26.2984 + 3.9197 = 22.3787 and 30.2181 in$
5. Mark from the end of the conduit: 8 in
1. Subtract the take-up from the stub height, because the bend uses that much length. Line the mark up with the bender's arrow
  $13 - 5$ $= 8 in$
6. Mark from the back of the first 90 (star): 36 in
1. Star (back-of-bend) method: measure the full distance from the back of the first 90, then bend with the mark on the star
  $mark$ $= 36 in$
2. Arrow method, for short pieces: subtract the take-up, then bend with the bender facing the other way
  $36 - 6$ $= 30 in$
7. Distance between bend marks: 13.066 in
1. Find the multiplier for 22.5° bends: 1 divided by the sine of the angle. It tells you how far apart the marks go
  $multiplier$ $= \frac{1}{sin 22.5°}$ $= 2.6131$
2. Multiply the offset depth by the multiplier to get the distance between the two bend marks
  $5 \times 2.6131$ $= 13.0656 in$
3. Work out the shrink, because the slanted section uses up length: depth × tan(22.5° ÷ 2)
  $5 \times 0.1989$ $= 0.9946 in$
4. Place the first mark (the bend nearest the obstacle): add the shrink to the distance to the obstacle
  $32 + 0.9946$ $= 32.9946 in$
5. Place the second mark by measuring back from the first by the distance between marks
  $32.9946 - 13.0656$ $= 19.9289 in$
8. Distance between bend marks: 5.226 in
1. Find the multiplier for 22.5° bends: 1 divided by the sine of the angle. It tells you how far apart the marks go
  $multiplier$ $= \frac{1}{sin 22.5°}$ $= 2.6131$
2. Multiply the offset depth by the multiplier to get the distance between the two bend marks
  $2 \times 2.6131$ $= 5.2263 in$
3. Work out the shrink, because the slanted section uses up length: depth × tan(22.5° ÷ 2)
  $2 \times 0.1989$ $= 0.3978 in$
4. Place the first mark (the bend nearest the obstacle): add the shrink to the distance to the obstacle
  $40 + 0.3978$ $= 40.3978 in$
5. Place the second mark by measuring back from the first by the distance between marks
  $40.3978 - 5.2263$ $= 35.1716 in$
9. Mark from the back of the first 90 (star): 35 in
1. Star (back-of-bend) method: measure the full distance from the back of the first 90, then bend with the mark on the star
  $mark$ $= 35 in$
2. Arrow method, for short pieces: subtract the take-up, then bend with the bender facing the other way
  $35 - 6$ $= 29 in$
10. Center mark from the end: 34.402 in
1. Each side bend is half the 60° center bend. The spacing multiplier is 1 divided by the sine of 30°
  $multiplier$ $= \frac{1}{sin 30°}$ $= 2$
2. Multiply the obstacle height by the multiplier to get the distance from the center mark to each outer mark
  $1.5 \times 2$ $= 3 in$
3. Work out the shrink, because climbing the obstacle uses up length: height × tan(30° ÷ 2)
  $1.5 \times 0.2679$ $= 0.4019 in$
4. Place the center mark: add the shrink to the distance to the obstacle's center
  $34 + 0.4019$ $= 34.4019 in$
5. Measure that spacing out on each side of the center mark for the two outer marks
  $34.4019 - 3 and 34.4019 + 3 = 31.4019 and 37.4019 in$