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Cubic Yard worksheet

Grade 6 · CCSS 6.G.A.2, 6.RP.A.3.d

Solve each problem and show your work. Round answers to 2 decimal places where needed.

1.
Problem 1.
- Measure by: Area × depth
- Area: 120 ft²
- Depth or thickness: 4 in
Find: Volume
Answer
2.
Problem 2.
- Measure by: Area × depth
- Area: 105 ft²
- Depth or thickness: 3 in
Find: Volume
Answer
3.
Problem 3.
- Measure by: Length × width × depth
- Length: 11 ft
- Width: 11 ft
- Depth or thickness: 4 in
Find: Volume
Answer
4.
Problem 4.
- Measure by: Length × width × depth
- Length: 14 ft
- Width: 9 ft
- Depth or thickness: 3 in
Find: Volume
Answer
5.
Problem 5.
- Measure by: Area × depth
- Area: 80 ft²
- Depth or thickness: 5 in
Find: Volume
Answer
6.
Problem 6.
- Measure by: Length × width × depth
- Length: 14 ft
- Width: 14 ft
- Depth or thickness: 3 in
Find: Volume
Answer
7.
Problem 7.
- Measure by: Area × depth
- Area: 150 ft²
- Depth or thickness: 4 in
Find: Volume
Answer
8.
Problem 8.
- Measure by: Length × width × depth
- Length: 10 ft
- Width: 11 ft
- Depth or thickness: 5 in
Find: Volume
Answer
9.
Problem 9.
- Measure by: Length × width × depth
- Length: 11 ft
- Width: 8 ft
- Depth or thickness: 3 in
Find: Volume
Answer
10.
Problem 10.
- Measure by: Length × width × depth
- Length: 11 ft
- Width: 13 ft
- Depth or thickness: 2 in
Find: Volume
Answer

Answer key: Cubic Yard worksheet

1. Volume: 1.48 yd³
1. Find the volume: multiply the area by the depth, after converting the depth to feet (4 in = 0.333333 ft)
  $120 \times 0.333333$ $= 40 ft³$
2. Divide by 27, because 1 yd³ = 3 ft × 3 ft × 3 ft = 27 ft³
  $\frac{40}{27}$ $= 1.481481 yd³$
3. For the metric figure, multiply by 0.028316846592, the cubic meters in one cubic foot
  $40 \times 0.028316846592$ $= 1.132674 m³$
2. Volume: 0.97 yd³
1. Find the volume: multiply the area by the depth, after converting the depth to feet (3 in = 0.25 ft)
  $105 \times 0.25$ $= 26.25 ft³$
2. Divide by 27, because 1 yd³ = 3 ft × 3 ft × 3 ft = 27 ft³
  $\frac{26.25}{27}$ $= 0.972222 yd³$
3. For the metric figure, multiply by 0.028316846592, the cubic meters in one cubic foot
  $26.25 \times 0.028316846592$ $= 0.743317 m³$
3. Volume: 1.49 yd³
1. Find the area: convert the length and width to feet, then multiply them
  $11 \times 11$ $= 121 ft²$
2. Find the volume: multiply the area by the depth, after converting the depth to feet (4 in = 0.333333 ft)
  $121 \times 0.333333$ $= 40.333333 ft³$
3. Divide by 27, because 1 yd³ = 3 ft × 3 ft × 3 ft = 27 ft³
  $\frac{40.333333}{27}$ $= 1.493827 yd³$
4. For the metric figure, multiply by 0.028316846592, the cubic meters in one cubic foot
  $40.333333 \times 0.028316846592$ $= 1.142113 m³$
4. Volume: 1.17 yd³
1. Find the area: convert the length and width to feet, then multiply them
  $14 \times 9$ $= 126 ft²$
2. Find the volume: multiply the area by the depth, after converting the depth to feet (3 in = 0.25 ft)
  $126 \times 0.25$ $= 31.5 ft³$
3. Divide by 27, because 1 yd³ = 3 ft × 3 ft × 3 ft = 27 ft³
  $\frac{31.5}{27}$ $= 1.166667 yd³$
4. For the metric figure, multiply by 0.028316846592, the cubic meters in one cubic foot
  $31.5 \times 0.028316846592$ $= 0.891981 m³$
5. Volume: 1.23 yd³
1. Find the volume: multiply the area by the depth, after converting the depth to feet (5 in = 0.416667 ft)
  $80 \times 0.416667$ $= 33.333333 ft³$
2. Divide by 27, because 1 yd³ = 3 ft × 3 ft × 3 ft = 27 ft³
  $\frac{33.333333}{27}$ $= 1.234568 yd³$
3. For the metric figure, multiply by 0.028316846592, the cubic meters in one cubic foot
  $33.333333 \times 0.028316846592$ $= 0.943895 m³$
6. Volume: 1.81 yd³
1. Find the area: convert the length and width to feet, then multiply them
  $14 \times 14$ $= 196 ft²$
2. Find the volume: multiply the area by the depth, after converting the depth to feet (3 in = 0.25 ft)
  $196 \times 0.25$ $= 49 ft³$
3. Divide by 27, because 1 yd³ = 3 ft × 3 ft × 3 ft = 27 ft³
  $\frac{49}{27}$ $= 1.814815 yd³$
4. For the metric figure, multiply by 0.028316846592, the cubic meters in one cubic foot
  $49 \times 0.028316846592$ $= 1.387525 m³$
7. Volume: 1.85 yd³
1. Find the volume: multiply the area by the depth, after converting the depth to feet (4 in = 0.333333 ft)
  $150 \times 0.333333$ $= 50 ft³$
2. Divide by 27, because 1 yd³ = 3 ft × 3 ft × 3 ft = 27 ft³
  $\frac{50}{27}$ $= 1.851852 yd³$
3. For the metric figure, multiply by 0.028316846592, the cubic meters in one cubic foot
  $50 \times 0.028316846592$ $= 1.415842 m³$
8. Volume: 1.7 yd³
1. Find the area: convert the length and width to feet, then multiply them
  $10 \times 11$ $= 110 ft²$
2. Find the volume: multiply the area by the depth, after converting the depth to feet (5 in = 0.416667 ft)
  $110 \times 0.416667$ $= 45.833333 ft³$
3. Divide by 27, because 1 yd³ = 3 ft × 3 ft × 3 ft = 27 ft³
  $\frac{45.833333}{27}$ $= 1.697531 yd³$
4. For the metric figure, multiply by 0.028316846592, the cubic meters in one cubic foot
  $45.833333 \times 0.028316846592$ $= 1.297855 m³$
9. Volume: 0.81 yd³
1. Find the area: convert the length and width to feet, then multiply them
  $11 \times 8$ $= 88 ft²$
2. Find the volume: multiply the area by the depth, after converting the depth to feet (3 in = 0.25 ft)
  $88 \times 0.25$ $= 22 ft³$
3. Divide by 27, because 1 yd³ = 3 ft × 3 ft × 3 ft = 27 ft³
  $\frac{22}{27}$ $= 0.814815 yd³$
4. For the metric figure, multiply by 0.028316846592, the cubic meters in one cubic foot
  $22 \times 0.028316846592$ $= 0.622971 m³$
10. Volume: 0.88 yd³
1. Find the area: convert the length and width to feet, then multiply them
  $11 \times 13$ $= 143 ft²$
2. Find the volume: multiply the area by the depth, after converting the depth to feet (2 in = 0.166667 ft)
  $143 \times 0.166667$ $= 23.833333 ft³$
3. Divide by 27, because 1 yd³ = 3 ft × 3 ft × 3 ft = 27 ft³
  $\frac{23.833333}{27}$ $= 0.882716 yd³$
4. For the metric figure, multiply by 0.028316846592, the cubic meters in one cubic foot
  $23.833333 \times 0.028316846592$ $= 0.674885 m³$