Electricity Cost worksheet

1. Cost per month: $20.37

1. Find the power in watts: amps times volts. This assumes the appliance always draws its full rated current

   $10\text{\hspace{0.17em}A}\times 125\text{\hspace{0.17em}V}$$=\mathrm{1,250}\text{\hspace{0.17em}W}$

2. Turn watts into kilowatts, the unit your bill uses (1 kW = 1,000 W)

   $\frac{\mathrm{1,250}\text{\hspace{0.17em}W}}{\mathrm{1,000}}$$=1.25\text{\hspace{0.17em}kW}$

3. Find the energy used each day: kilowatts times hours of use

   $1.25\text{\hspace{0.17em}kW}\times 5\text{\hspace{0.17em}h}$$=6.25\text{\hspace{0.17em}kWh}$

4. Find the cost for each day of use: energy times your price per kWh

   $6.25\text{\hspace{0.17em}kWh}\times \mathrm{\$0.15}$$=\mathrm{\$0.94}$

5. Count the days of use in a year: days per week times 365, divided by the 7 days in a week

   $\frac{5\times 365}{7}$$=260.7143\text{\hspace{0.17em}days}$

6. Find the yearly cost: the cost per day times the days of use

   $\mathrm{\$0.94}\times 260.7143$$=\mathrm{\$244.42}$

7. Split the yearly cost over 12 months to get an average month

   $\frac{\mathrm{\$244.42}}{12}$$=\mathrm{\$20.37}$

2. Cost per month: $31.63

1. Turn watts into kilowatts, the unit your bill uses (1 kW = 1,000 W)

   $\frac{\mathrm{1,300}\text{\hspace{0.17em}W}}{\mathrm{1,000}}$$=1.3\text{\hspace{0.17em}kW}$

2. Find the energy used each day: kilowatts times hours of use

   $1.3\text{\hspace{0.17em}kW}\times 4\text{\hspace{0.17em}h}$$=5.2\text{\hspace{0.17em}kWh}$

3. Find the cost for each day of use: energy times your price per kWh

   $5.2\text{\hspace{0.17em}kWh}\times \mathrm{\$0.20}$$=\mathrm{\$1.04}$

4. Count the days of use in a year: days per week times 365, divided by the 7 days in a week

   $\frac{7\times 365}{7}$$=365\text{\hspace{0.17em}days}$

5. Find the yearly cost: the cost per day times the days of use

   $\mathrm{\$1.04}\times 365$$=\mathrm{\$379.60}$

6. Split the yearly cost over 12 months to get an average month

   $\frac{\mathrm{\$379.60}}{12}$$=\mathrm{\$31.63}$

3. Cost per month: $30.42

1. Turn watts into kilowatts, the unit your bill uses (1 kW = 1,000 W)

   $\frac{\mathrm{1,250}\text{\hspace{0.17em}W}}{\mathrm{1,000}}$$=1.25\text{\hspace{0.17em}kW}$

2. Find the energy used each day: kilowatts times hours of use

   $1.25\text{\hspace{0.17em}kW}\times 4\text{\hspace{0.17em}h}$$=5\text{\hspace{0.17em}kWh}$

3. Find the cost for each day of use: energy times your price per kWh

   $5\text{\hspace{0.17em}kWh}\times \mathrm{\$0.20}$$=\mathrm{\$1.00}$

4. Count the days of use in a year: days per week times 365, divided by the 7 days in a week

   $\frac{7\times 365}{7}$$=365\text{\hspace{0.17em}days}$

5. Find the yearly cost: the cost per day times the days of use

   $\mathrm{\$1.00}\times 365$$=\mathrm{\$365.00}$

6. Split the yearly cost over 12 months to get an average month

   $\frac{\mathrm{\$365.00}}{12}$$=\mathrm{\$30.42}$

4. Cost per month: $42.81

1. Find the power in watts: amps times volts. This assumes the appliance always draws its full rated current

   $14\text{\hspace{0.17em}A}\times 138\text{\hspace{0.17em}V}$$=\mathrm{1,932}\text{\hspace{0.17em}W}$

2. Turn watts into kilowatts, the unit your bill uses (1 kW = 1,000 W)

   $\frac{\mathrm{1,932}\text{\hspace{0.17em}W}}{\mathrm{1,000}}$$=1.932\text{\hspace{0.17em}kW}$

3. Find the energy used each day: kilowatts times hours of use

   $1.932\text{\hspace{0.17em}kW}\times 5\text{\hspace{0.17em}h}$$=9.66\text{\hspace{0.17em}kWh}$

4. Find the cost for each day of use: energy times your price per kWh

   $9.66\text{\hspace{0.17em}kWh}\times \mathrm{\$0.17}$$=\mathrm{\$1.64}$

5. Count the days of use in a year: days per week times 365, divided by the 7 days in a week

   $\frac{6\times 365}{7}$$=312.8571\text{\hspace{0.17em}days}$

6. Find the yearly cost: the cost per day times the days of use

   $\mathrm{\$1.64}\times 312.8571$$=\mathrm{\$513.77}$

7. Split the yearly cost over 12 months to get an average month

   $\frac{\mathrm{\$513.77}}{12}$$=\mathrm{\$42.81}$

5. Cost per month: $10.84

1. Find the power in watts: amps times volts. This assumes the appliance always draws its full rated current

   $9\text{\hspace{0.17em}A}\times 110\text{\hspace{0.17em}V}$$=990\text{\hspace{0.17em}W}$

2. Turn watts into kilowatts, the unit your bill uses (1 kW = 1,000 W)

   $\frac{990\text{\hspace{0.17em}W}}{\mathrm{1,000}}$$=0.99\text{\hspace{0.17em}kW}$

3. Find the energy used each day: kilowatts times hours of use

   $0.99\text{\hspace{0.17em}kW}\times 3\text{\hspace{0.17em}h}$$=2.97\text{\hspace{0.17em}kWh}$

4. Find the cost for each day of use: energy times your price per kWh

   $2.97\text{\hspace{0.17em}kWh}\times \mathrm{\$0.14}$$=\mathrm{\$0.42}$

5. Count the days of use in a year: days per week times 365, divided by the 7 days in a week

   $\frac{6\times 365}{7}$$=312.8571\text{\hspace{0.17em}days}$

6. Find the yearly cost: the cost per day times the days of use

   $\mathrm{\$0.42}\times 312.8571$$=\mathrm{\$130.09}$

7. Split the yearly cost over 12 months to get an average month

   $\frac{\mathrm{\$130.09}}{12}$$=\mathrm{\$10.84}$

6. Cost per month: $17.79

1. Find the power in watts: amps times volts. This assumes the appliance always draws its full rated current

   $13\text{\hspace{0.17em}A}\times 70\text{\hspace{0.17em}V}$$=910\text{\hspace{0.17em}W}$

2. Turn watts into kilowatts, the unit your bill uses (1 kW = 1,000 W)

   $\frac{910\text{\hspace{0.17em}W}}{\mathrm{1,000}}$$=0.91\text{\hspace{0.17em}kW}$

3. Find the energy used each day: kilowatts times hours of use

   $0.91\text{\hspace{0.17em}kW}\times 5\text{\hspace{0.17em}h}$$=4.55\text{\hspace{0.17em}kWh}$

4. Find the cost for each day of use: energy times your price per kWh

   $4.55\text{\hspace{0.17em}kWh}\times \mathrm{\$0.18}$$=\mathrm{\$0.82}$

5. Count the days of use in a year: days per week times 365, divided by the 7 days in a week

   $\frac{5\times 365}{7}$$=260.7143\text{\hspace{0.17em}days}$

6. Find the yearly cost: the cost per day times the days of use

   $\mathrm{\$0.82}\times 260.7143$$=\mathrm{\$213.53}$

7. Split the yearly cost over 12 months to get an average month

   $\frac{\mathrm{\$213.53}}{12}$$=\mathrm{\$17.79}$

7. Cost per month: $22.54

1. Find the power in watts: amps times volts. This assumes the appliance always draws its full rated current

   $13\text{\hspace{0.17em}A}\times 95\text{\hspace{0.17em}V}$$=\mathrm{1,235}\text{\hspace{0.17em}W}$

2. Turn watts into kilowatts, the unit your bill uses (1 kW = 1,000 W)

   $\frac{\mathrm{1,235}\text{\hspace{0.17em}W}}{\mathrm{1,000}}$$=1.235\text{\hspace{0.17em}kW}$

3. Find the energy used each day: kilowatts times hours of use

   $1.235\text{\hspace{0.17em}kW}\times 5\text{\hspace{0.17em}h}$$=6.175\text{\hspace{0.17em}kWh}$

4. Find the cost for each day of use: energy times your price per kWh

   $6.175\text{\hspace{0.17em}kWh}\times \mathrm{\$0.14}$$=\mathrm{\$0.86}$

5. Count the days of use in a year: days per week times 365, divided by the 7 days in a week

   $\frac{6\times 365}{7}$$=312.8571\text{\hspace{0.17em}days}$

6. Find the yearly cost: the cost per day times the days of use

   $\mathrm{\$0.86}\times 312.8571$$=\mathrm{\$270.47}$

7. Split the yearly cost over 12 months to get an average month

   $\frac{\mathrm{\$270.47}}{12}$$=\mathrm{\$22.54}$

8. Cost per month: $12.91

1. Find the power in watts: amps times volts. This assumes the appliance always draws its full rated current

   $11\text{\hspace{0.17em}A}\times 120\text{\hspace{0.17em}V}$$=\mathrm{1,320}\text{\hspace{0.17em}W}$

2. Turn watts into kilowatts, the unit your bill uses (1 kW = 1,000 W)

   $\frac{\mathrm{1,320}\text{\hspace{0.17em}W}}{\mathrm{1,000}}$$=1.32\text{\hspace{0.17em}kW}$

3. Find the energy used each day: kilowatts times hours of use

   $1.32\text{\hspace{0.17em}kW}\times 3\text{\hspace{0.17em}h}$$=3.96\text{\hspace{0.17em}kWh}$

4. Find the cost for each day of use: energy times your price per kWh

   $3.96\text{\hspace{0.17em}kWh}\times \mathrm{\$0.15}$$=\mathrm{\$0.59}$

5. Count the days of use in a year: days per week times 365, divided by the 7 days in a week

   $\frac{5\times 365}{7}$$=260.7143\text{\hspace{0.17em}days}$

6. Find the yearly cost: the cost per day times the days of use

   $\mathrm{\$0.59}\times 260.7143$$=\mathrm{\$154.86}$

7. Split the yearly cost over 12 months to get an average month

   $\frac{\mathrm{\$154.86}}{12}$$=\mathrm{\$12.91}$

9. Cost per month: $26.28

1. Turn watts into kilowatts, the unit your bill uses (1 kW = 1,000 W)

   $\frac{\mathrm{1,800}\text{\hspace{0.17em}W}}{\mathrm{1,000}}$$=1.8\text{\hspace{0.17em}kW}$

2. Find the energy used each day: kilowatts times hours of use

   $1.8\text{\hspace{0.17em}kW}\times 3\text{\hspace{0.17em}h}$$=5.4\text{\hspace{0.17em}kWh}$

3. Find the cost for each day of use: energy times your price per kWh

   $5.4\text{\hspace{0.17em}kWh}\times \mathrm{\$0.16}$$=\mathrm{\$0.86}$

4. Count the days of use in a year: days per week times 365, divided by the 7 days in a week

   $\frac{7\times 365}{7}$$=365\text{\hspace{0.17em}days}$

5. Find the yearly cost: the cost per day times the days of use

   $\mathrm{\$0.86}\times 365$$=\mathrm{\$315.36}$

6. Split the yearly cost over 12 months to get an average month

   $\frac{\mathrm{\$315.36}}{12}$$=\mathrm{\$26.28}$

10. Cost per month: $17.88

1. Turn watts into kilowatts, the unit your bill uses (1 kW = 1,000 W)

   $\frac{\mathrm{1,400}\text{\hspace{0.17em}W}}{\mathrm{1,000}}$$=1.4\text{\hspace{0.17em}kW}$

2. Find the energy used each day: kilowatts times hours of use

   $1.4\text{\hspace{0.17em}kW}\times 3\text{\hspace{0.17em}h}$$=4.2\text{\hspace{0.17em}kWh}$

3. Find the cost for each day of use: energy times your price per kWh

   $4.2\text{\hspace{0.17em}kWh}\times \mathrm{\$0.14}$$=\mathrm{\$0.59}$

4. Count the days of use in a year: days per week times 365, divided by the 7 days in a week

   $\frac{7\times 365}{7}$$=365\text{\hspace{0.17em}days}$

5. Find the yearly cost: the cost per day times the days of use

   $\mathrm{\$0.59}\times 365$$=\mathrm{\$214.62}$

6. Split the yearly cost over 12 months to get an average month

   $\frac{\mathrm{\$214.62}}{12}$$=\mathrm{\$17.88}$