Fielding Percentage worksheet

1. Fielding percentage: 0.974

1. Add up total chances: every putout, assist and error is a ball the fielder could have handled

   $\mathrm{TC}$$=225+450+18$$=693$

2. Divide the plays made (putouts plus assists) by total chances to see how often the play was clean

   $\mathrm{FPCT}$$=\frac{225+450}{693}$$=\frac{675}{693}$$=0.974026$

3. Round to three decimals, the way box scores show it

   $0.974026\text{→}\text{.974}$

2. Fielding percentage: 0.966

1. Add up total chances: every putout, assist and error is a ball the fielder could have handled

   $\mathrm{TC}$$=200+260+16$$=476$

2. Divide the plays made (putouts plus assists) by total chances to see how often the play was clean

   $\mathrm{FPCT}$$=\frac{200+260}{476}$$=\frac{460}{476}$$=0.966387$

3. Round to three decimals, the way box scores show it

   $0.966387\text{→}\text{.966}$

3. Fielding percentage: 0.978

1. Add up total chances: every putout, assist and error is a ball the fielder could have handled

   $\mathrm{TC}$$=350+460+18$$=828$

2. Divide the plays made (putouts plus assists) by total chances to see how often the play was clean

   $\mathrm{FPCT}$$=\frac{350+460}{828}$$=\frac{810}{828}$$=0.978261$

3. Round to three decimals, the way box scores show it

   $0.978261\text{→}\text{.978}$

4. Fielding percentage: 0.975

1. Add up total chances: every putout, assist and error is a ball the fielder could have handled

   $\mathrm{TC}$$=160+380+14$$=554$

2. Divide the plays made (putouts plus assists) by total chances to see how often the play was clean

   $\mathrm{FPCT}$$=\frac{160+380}{554}$$=\frac{540}{554}$$=0.974729$

3. Round to three decimals, the way box scores show it

   $0.974729\text{→}\text{.975}$

5. Fielding percentage: 0.976

1. Add up total chances: every putout, assist and error is a ball the fielder could have handled

   $\mathrm{TC}$$=180+390+14$$=584$

2. Divide the plays made (putouts plus assists) by total chances to see how often the play was clean

   $\mathrm{FPCT}$$=\frac{180+390}{584}$$=\frac{570}{584}$$=0.976027$

3. Round to three decimals, the way box scores show it

   $0.976027\text{→}\text{.976}$

6. Fielding percentage: 0.982

1. Add up total chances: every putout, assist and error is a ball the fielder could have handled

   $\mathrm{TC}$$=260+400+12$$=672$

2. Divide the plays made (putouts plus assists) by total chances to see how often the play was clean

   $\mathrm{FPCT}$$=\frac{260+400}{672}$$=\frac{660}{672}$$=0.982143$

3. Round to three decimals, the way box scores show it

   $0.982143\text{→}\text{.982}$

7. Fielding percentage: 0.982

1. Add up total chances: every putout, assist and error is a ball the fielder could have handled

   $\mathrm{TC}$$=250+400+12$$=662$

2. Divide the plays made (putouts plus assists) by total chances to see how often the play was clean

   $\mathrm{FPCT}$$=\frac{250+400}{662}$$=\frac{650}{662}$$=0.981873$

3. Round to three decimals, the way box scores show it

   $0.981873\text{→}\text{.982}$

8. Fielding percentage: 0.974

1. Add up total chances: every putout, assist and error is a ball the fielder could have handled

   $\mathrm{TC}$$=280+330+16$$=626$

2. Divide the plays made (putouts plus assists) by total chances to see how often the play was clean

   $\mathrm{FPCT}$$=\frac{280+330}{626}$$=\frac{610}{626}$$=0.974441$

3. Round to three decimals, the way box scores show it

   $0.974441\text{→}\text{.974}$

9. Fielding percentage: 0.983

1. Add up total chances: every putout, assist and error is a ball the fielder could have handled

   $\mathrm{TC}$$=260+450+12$$=722$

2. Divide the plays made (putouts plus assists) by total chances to see how often the play was clean

   $\mathrm{FPCT}$$=\frac{260+450}{722}$$=\frac{710}{722}$$=0.98338$

3. Round to three decimals, the way box scores show it

   $0.98338\text{→}\text{.983}$

10. Fielding percentage: 0.973

1. Add up total chances: every putout, assist and error is a ball the fielder could have handled

   $\mathrm{TC}$$=160+500+18$$=678$

2. Divide the plays made (putouts plus assists) by total chances to see how often the play was clean

   $\mathrm{FPCT}$$=\frac{160+500}{678}$$=\frac{660}{678}$$=0.973451$

3. Round to three decimals, the way box scores show it

   $0.973451\text{→}\text{.973}$