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Friction Loss worksheet

Grade 12 to college

Solve each problem and show your work. Round answers to 2 decimal places where needed.

  1. Problem 1.
    • Method: Darcy–Weisbach
    • Pipe or tube: Type K copper
    • Pipe size (the size it's sold as): 1 1/2 in
    • Flow rate: 11 gpm
    • Length of pipe: 120 ft
    • Pipe roughness: Other roughness
    • Absolute roughness: 0.04 mm
    • Kinematic viscosity: 0.8 mm²/s

    Find: Pressure drop

  2. Problem 2.
    • Method: Hazen–Williams
    • Pipe or tube: Type L copper
    • Pipe size (the size it's sold as): 3/8 in
    • Flow rate: 11 gpm
    • Length of pipe: 120 ft
    • Hazen–Williams C: 140: copper tube

    Find: Pressure drop

  3. Problem 3.
    • Method: Darcy–Weisbach
    • Pipe or tube: PEX (CTS, SDR 9)
    • Pipe size (the size it's sold as): 1 1/2 in
    • Flow rate: 9 gpm
    • Length of pipe: 75 ft
    • Pipe roughness: Other roughness
    • Absolute roughness: 0.04 mm
    • Kinematic viscosity: 1.1 mm²/s

    Find: Pressure drop

  4. Problem 4.
    • Method: Darcy–Weisbach
    • Pipe or tube: PEX (CTS, SDR 9)
    • Pipe size (the size it's sold as): 5/8 in
    • Flow rate: 14 gpm
    • Length of pipe: 116 ft
    • Pipe roughness: 0.26 mm: cast iron
    • Kinematic viscosity: 1.2 mm²/s

    Find: Pressure drop

  5. Problem 5.
    • Method: Darcy–Weisbach
    • Pipe or tube: Schedule 80 PVC
    • Pipe size (the size it's sold as): 3/4 in
    • Flow rate: 12 gpm
    • Length of pipe: 80 ft
    • Pipe roughness: 0.26 mm: cast iron
    • Kinematic viscosity: 1.075 mm²/s

    Find: Pressure drop

  6. Problem 6.
    • Method: Darcy–Weisbach
    • Pipe or tube: Schedule 40 steel
    • Pipe size (the size it's sold as): 1 in
    • Flow rate: 10 gpm
    • Length of pipe: 100 ft
    • Pipe roughness: 0.0015 mm: drawn tubing, copper, plastic
    • Kinematic viscosity: 0.65 mm²/s

    Find: Pressure drop

  7. Problem 7.
    • Method: Darcy–Weisbach
    • Pipe or tube: Type K copper
    • Pipe size (the size it's sold as): 1 1/2 in
    • Flow rate: 9 gpm
    • Length of pipe: 115 ft
    • Pipe roughness: 0.15 mm: galvanized iron
    • Kinematic viscosity: 1 mm²/s

    Find: Pressure drop

  8. Problem 8.
    • Method: Darcy–Weisbach
    • Pipe or tube: Type K copper
    • Pipe size (the size it's sold as): 3/4 in
    • Flow rate: 11 gpm
    • Length of pipe: 85 ft
    • Pipe roughness: Other roughness
    • Absolute roughness: 0.06 mm
    • Kinematic viscosity: 1 mm²/s

    Find: Pressure drop

  9. Problem 9.
    • Method: Hazen–Williams
    • Pipe or tube: Type L copper
    • Pipe size (the size it's sold as): 3/4 in
    • Flow rate: 10 gpm
    • Length of pipe: 90 ft
    • Hazen–Williams C: Other C value
    • C value: 120

    Find: Pressure drop

  10. Problem 10.
    • Method: Darcy–Weisbach
    • Pipe or tube: PEX (CTS, SDR 9)
    • Pipe size (the size it's sold as): 1 1/4 in
    • Flow rate: 10 gpm
    • Length of pipe: 80 ft
    • Pipe roughness: 0.045 mm: commercial steel
    • Kinematic viscosity: 0.75 mm²/s

    Find: Pressure drop

Answer key: Friction Loss worksheet

  1. 1. Pressure drop: 0.719 psi

    1. Find how fast the water moves: divide the flow by the pipe's inside area (bore 1.481 in = 0.037617 m)

      0.000693990.00111139=0.624435 m/s
    2. Find the Reynolds number, Re = V × d ÷ ν. It shows whether the flow is smooth or swirling

      Re=0.624435×0.0376170.0000008=29,362
    3. Find the friction factor f from the Colebrook–White equation. It uses the roughness compared with the bore, ε ÷ d = 0.00106334

      f=0.026207
    4. Find the head lost over the run with Darcy–Weisbach: h = f × (L ÷ d) × V² ÷ (2g)

      h=0.026207×36.5760.037617×0.62443522×9.80665=0.506578 m
    5. Turn head into pressure using the weight of water: ρ g h (water at 20 °C), in psi (about 0.4328 psi per foot of head)

      998.2×9.80665×0.5065786,894.757293=0.719226 psi
  2. 2. Pressure drop: 298.878 psi

    1. Find the head lost in each 100 ft of pipe with Hazen–Williams: 0.2083 × (100 ÷ C)^1.852 × Q^1.852 ÷ d^4.8655. Here C = 140 and the bore is 0.43 in

      0.2083×(100140)1.852×111.8520.434.8655=575.544132 ft per 100 ft
    2. Scale that up to the full length of the run

      575.544132×120100=690.652958 ft
    3. Turn head into pressure using the weight of water: ρ g h (water at 20 °C), in psi (about 0.4328 psi per foot of head)

      998.2×9.80665×210.5110226,894.757293=298.878102 psi
  3. 3. Pressure drop: 0.717 psi

    1. Find how fast the water moves: divide the flow by the pipe's inside area (bore 1.264 in = 0.032106 m)

      0.000567810.00080956=0.701379 m/s
    2. Find the Reynolds number, Re = V × d ÷ ν. It shows whether the flow is smooth or swirling

      Re=0.701379×0.0321060.0000011=20,471
    3. Find the friction factor f from the Colebrook–White equation. It uses the roughness compared with the bore, ε ÷ d = 0.00124589

      f=0.028296
    4. Find the head lost over the run with Darcy–Weisbach: h = f × (L ÷ d) × V² ÷ (2g)

      h=0.028296×22.860.032106×0.70137922×9.80665=0.505333 m
    5. Turn head into pressure using the weight of water: ρ g h (water at 20 °C), in psi (about 0.4328 psi per foot of head)

      998.2×9.80665×0.5053336,894.757293=0.717459 psi
  4. 4. Pressure drop: 211.536 psi

    1. Find how fast the water moves: divide the flow by the pipe's inside area (bore 0.584 in = 0.014834 m)

      0.000883260.00017282=5.111012 m/s
    2. Find the Reynolds number, Re = V × d ÷ ν. It shows whether the flow is smooth or swirling

      Re=5.111012×0.0148340.0000012=63,179
    3. Find the friction factor f from the Colebrook–White equation. It uses the roughness compared with the bore, ε ÷ d = 0.01752777

      f=0.046933
    4. Find the head lost over the run with Darcy–Weisbach: h = f × (L ÷ d) × V² ÷ (2g)

      h=0.046933×35.35680.014834×5.11101222×9.80665=148.992852 m
    5. Turn head into pressure using the weight of water: ρ g h (water at 20 °C), in psi (about 0.4328 psi per foot of head)

      998.2×9.80665×148.9928526,894.757293=211.536197 psi
  5. 5. Pressure drop: 34.618 psi

    1. Find how fast the water moves: divide the flow by the pipe's inside area (bore 0.722 in = 0.018339 m)

      0.000757080.00026414=2.866232 m/s
    2. Find the Reynolds number, Re = V × d ÷ ν. It shows whether the flow is smooth or swirling

      Re=2.866232×0.0183390.000001075=48,896
    3. Find the friction factor f from the Colebrook–White equation. It uses the roughness compared with the bore, ε ÷ d = 0.01417759

      f=0.04378
    4. Find the head lost over the run with Darcy–Weisbach: h = f × (L ÷ d) × V² ÷ (2g)

      h=0.04378×24.3840.018339×2.86623222×9.80665=24.382533 m
    5. Turn head into pressure using the weight of water: ρ g h (water at 20 °C), in psi (about 0.4328 psi per foot of head)

      998.2×9.80665×24.3825336,894.757293=34.61769 psi
  6. 6. Pressure drop: 2.273 psi

    1. Find how fast the water moves: divide the flow by the pipe's inside area (bore 1.049 in = 0.026645 m)

      0.00063090.00055758=1.131497 m/s
    2. Find the Reynolds number, Re = V × d ÷ ν. It shows whether the flow is smooth or swirling

      Re=1.131497×0.0266450.00000065=46,382
    3. Find the friction factor f from the Colebrook–White equation. It uses the roughness compared with the bore, ε ÷ d = 0.0000563

      f=0.02144
    4. Find the head lost over the run with Darcy–Weisbach: h = f × (L ÷ d) × V² ÷ (2g)

      h=0.02144×30.480.026645×1.13149722×9.80665=1.600961 m
    5. Turn head into pressure using the weight of water: ρ g h (water at 20 °C), in psi (about 0.4328 psi per foot of head)

      998.2×9.80665×1.6009616,894.757293=2.273004 psi
  7. 7. Pressure drop: 0.584 psi

    1. Find how fast the water moves: divide the flow by the pipe's inside area (bore 1.481 in = 0.037617 m)

      0.000567810.00111139=0.510901 m/s
    2. Find the Reynolds number, Re = V × d ÷ ν. It shows whether the flow is smooth or swirling

      Re=0.510901×0.0376170.000001=19,219
    3. Find the friction factor f from the Colebrook–White equation. It uses the roughness compared with the bore, ε ÷ d = 0.00398752

      f=0.033156
    4. Find the head lost over the run with Darcy–Weisbach: h = f × (L ÷ d) × V² ÷ (2g)

      h=0.033156×35.0520.037617×0.51090122×9.80665=0.411153 m
    5. Turn head into pressure using the weight of water: ρ g h (water at 20 °C), in psi (about 0.4328 psi per foot of head)

      998.2×9.80665×0.4111536,894.757293=0.583744 psi
  8. 8. Pressure drop: 17.562 psi

    1. Find how fast the water moves: divide the flow by the pipe's inside area (bore 0.745 in = 0.018923 m)

      0.000693990.00028124=2.467656 m/s
    2. Find the Reynolds number, Re = V × d ÷ ν. It shows whether the flow is smooth or swirling

      Re=2.467656×0.0189230.000001=46,695
    3. Find the friction factor f from the Colebrook–White equation. It uses the roughness compared with the bore, ε ÷ d = 0.00317074

      f=0.0291
    4. Find the head lost over the run with Darcy–Weisbach: h = f × (L ÷ d) × V² ÷ (2g)

      h=0.0291×25.9080.018923×2.46765622×9.80665=12.369616 m
    5. Turn head into pressure using the weight of water: ρ g h (water at 20 °C), in psi (about 0.4328 psi per foot of head)

      998.2×9.80665×12.3696166,894.757293=17.562061 psi
  9. 9. Pressure drop: 13.367 psi

    1. Find the head lost in each 100 ft of pipe with Hazen–Williams: 0.2083 × (100 ÷ C)^1.852 × Q^1.852 ÷ d^4.8655. Here C = 120 and the bore is 0.785 in

      0.2083×(100120)1.852×101.8520.7854.8655=34.320791 ft per 100 ft
    2. Scale that up to the full length of the run

      34.320791×90100=30.888712 ft
    3. Turn head into pressure using the weight of water: ρ g h (water at 20 °C), in psi (about 0.4328 psi per foot of head)

      998.2×9.80665×9.4148796,894.757293=13.367002 psi
  10. 10. Pressure drop: 2.039 psi

    1. Find how fast the water moves: divide the flow by the pipe's inside area (bore 1.069 in = 0.027153 m)

      0.00063090.00057905=1.089555 m/s
    2. Find the Reynolds number, Re = V × d ÷ ν. It shows whether the flow is smooth or swirling

      Re=1.089555×0.0271530.00000075=39,446
    3. Find the friction factor f from the Colebrook–White equation. It uses the roughness compared with the bore, ε ÷ d = 0.0016573

      f=0.026421
    4. Find the head lost over the run with Darcy–Weisbach: h = f × (L ÷ d) × V² ÷ (2g)

      h=0.026421×24.3840.027153×1.08955522×9.80665=1.436143 m
    5. Turn head into pressure using the weight of water: ρ g h (water at 20 °C), in psi (about 0.4328 psi per foot of head)

      998.2×9.80665×1.4361436,894.757293=2.038999 psi