Grams to Moles worksheet

1. Mass: 57.07 g

1. Find the molar mass of H3O, the weight of one mole. Take each atom's weight times how many there are, then add them up

   $3\times 1.008+1\times 15.999$$=19.023\text{\hspace{0.17em}g/mol}$

2. Multiply the moles by the grams in one mole to get the mass in grams (m)

   $m$$=3\text{\hspace{0.17em}mol}\times 19.023\text{\hspace{0.17em}g/mol}$$=57.069\text{\hspace{0.17em}g}$

3. Multiply the moles by Avogadro's number, the count in one mole, to get the particles (N)

   $N$$=3\times 6.02214076e+23$$=1.806642e+24$

4. Each H3O unit contains 4 atoms, so multiply to count every atom

   $1.806642e+24\times 4$$=7.226569e+24$

2. Amount of substance: 1.74 mol

1. Find the molar mass of H4O, the weight of one mole. Take each atom's weight times how many there are, then add them up

   $4\times 1.008+1\times 15.999$$=20.031\text{\hspace{0.17em}g/mol}$

2. Divide the particles by Avogadro's number, the count in one mole, to get the moles (n)

   $n$$=\frac{1.05e+24}{6.02214076e+23}$$=1.7435660205\text{\hspace{0.17em}mol}$

3. Multiply the moles by the grams in one mole to get the mass in grams (m)

   $m$$=1.7435660205\text{\hspace{0.17em}mol}\times 20.031\text{\hspace{0.17em}g/mol}$$=34.925371\text{\hspace{0.17em}g}$

4. Each H4O unit contains 5 atoms, so multiply to count every atom

   $1.05e+24\times 5$$=5.25e+24$

3. Amount of substance: 1.78 mol

1. Find the molar mass of H2O, the weight of one mole. Take each atom's weight times how many there are, then add them up

   $2\times 1.008+1\times 15.999$$=18.015\text{\hspace{0.17em}g/mol}$

2. Divide the mass by the molar mass to find how many moles (n) you have

   $n$$=\frac{32\text{\hspace{0.17em}g}}{18.015\text{\hspace{0.17em}g/mol}}$$=1.776298\text{\hspace{0.17em}mol}$

3. Multiply the moles by Avogadro's number, the count in one mole, to get the particles (N)

   $N$$=1.776298\times 6.02214076e+23$$=1.069711e+24$

4. Each H2O unit contains 3 atoms, so multiply to count every atom

   $1.069711e+24\times 3$$=3.209134e+24$

4. Amount of substance: 2.16 mol

1. Find the molar mass of H2O, the weight of one mole. Take each atom's weight times how many there are, then add them up

   $2\times 1.008+1\times 15.999$$=18.015\text{\hspace{0.17em}g/mol}$

2. Divide the mass by the molar mass to find how many moles (n) you have

   $n$$=\frac{39\text{\hspace{0.17em}g}}{18.015\text{\hspace{0.17em}g/mol}}$$=2.164863\text{\hspace{0.17em}mol}$

3. Multiply the moles by Avogadro's number, the count in one mole, to get the particles (N)

   $N$$=2.164863\times 6.02214076e+23$$=1.303711e+24$

4. Each H2O unit contains 3 atoms, so multiply to count every atom

   $1.303711e+24\times 3$$=3.911132e+24$

5. Mass: 57 g

1. Multiply the moles by the grams in one mole to get the mass in grams (m)

   $m$$=3\text{\hspace{0.17em}mol}\times 19\text{\hspace{0.17em}g/mol}$$=57\text{\hspace{0.17em}g}$

2. Multiply the moles by Avogadro's number, the count in one mole, to get the particles (N)

   $N$$=3\times 6.02214076e+23$$=1.806642e+24$

6. Amount of substance: 1.8 mol

1. Find the molar mass of H2O, the weight of one mole. Take each atom's weight times how many there are, then add them up

   $2\times 1.008+1\times 15.999$$=18.015\text{\hspace{0.17em}g/mol}$

2. Divide the mass by the molar mass to find how many moles (n) you have

   $n$$=\frac{32.5\text{\hspace{0.17em}g}}{18.015\text{\hspace{0.17em}g/mol}}$$=1.804052\text{\hspace{0.17em}mol}$

3. Multiply the moles by Avogadro's number, the count in one mole, to get the particles (N)

   $N$$=1.804052\times 6.02214076e+23$$=1.086426e+24$

4. Each H2O unit contains 3 atoms, so multiply to count every atom

   $1.086426e+24\times 3$$=3.259277e+24$

7. Amount of substance: 2.35 mol

1. Find the molar mass of H1O, the weight of one mole. Take each atom's weight times how many there are, then add them up

   $1\times 1.008+1\times 15.999$$=17.007\text{\hspace{0.17em}g/mol}$

2. Divide the mass by the molar mass to find how many moles (n) you have

   $n$$=\frac{40\text{\hspace{0.17em}g}}{17.007\text{\hspace{0.17em}g/mol}}$$=2.351973\text{\hspace{0.17em}mol}$

3. Multiply the moles by Avogadro's number, the count in one mole, to get the particles (N)

   $N$$=2.351973\times 6.02214076e+23$$=1.416391e+24$

4. Each H1O unit contains 2 atoms, so multiply to count every atom

   $1.416391e+24\times 2$$=2.832782e+24$

8. Amount of substance: 2.99 mol

1. Find the molar mass of H2O, the weight of one mole. Take each atom's weight times how many there are, then add them up

   $2\times 1.008+1\times 15.999$$=18.015\text{\hspace{0.17em}g/mol}$

2. Divide the particles by Avogadro's number, the count in one mole, to get the moles (n)

   $n$$=\frac{1.8e+24}{6.02214076e+23}$$=2.9889703209\text{\hspace{0.17em}mol}$

3. Multiply the moles by the grams in one mole to get the mass in grams (m)

   $m$$=2.9889703209\text{\hspace{0.17em}mol}\times 18.015\text{\hspace{0.17em}g/mol}$$=53.8463\text{\hspace{0.17em}g}$

4. Each H2O unit contains 3 atoms, so multiply to count every atom

   $1.8e+24\times 3$$=5.4e+24$

9. Amount of substance: 2.16 mol

1. Divide the particles by Avogadro's number, the count in one mole, to get the moles (n)

   $n$$=\frac{1.3e+24}{6.02214076e+23}$$=2.1587007873\text{\hspace{0.17em}mol}$

2. Multiply the moles by the grams in one mole to get the mass in grams (m)

   $m$$=2.1587007873\text{\hspace{0.17em}mol}\times 16\text{\hspace{0.17em}g/mol}$$=34.539213\text{\hspace{0.17em}g}$

10. Amount of substance: 2.45 mol

1. Find the molar mass of H3O, the weight of one mole. Take each atom's weight times how many there are, then add them up

   $3\times 1.008+1\times 15.999$$=19.023\text{\hspace{0.17em}g/mol}$

2. Divide the particles by Avogadro's number, the count in one mole, to get the moles (n)

   $n$$=\frac{1.475e+24}{6.02214076e+23}$$=2.4492951241\text{\hspace{0.17em}mol}$

3. Multiply the moles by the grams in one mole to get the mass in grams (m)

   $m$$=2.4492951241\text{\hspace{0.17em}mol}\times 19.023\text{\hspace{0.17em}g/mol}$$=46.592941\text{\hspace{0.17em}g}$

4. Each H3O unit contains 4 atoms, so multiply to count every atom

   $1.475e+24\times 4$$=5.9e+24$