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Grout worksheet

Grades 6–7 · CCSS 7.G.B.6

Solve each problem and show your work. Round answers to 2 decimal places where needed.

1.
Problem 1.
- Units: Metric (m², mm, kg)
- Area to tile: 10 m²
- Tile length: 320 mm
- Tile width: 350 mm
- Grout joint width: 2 mm
- Joint depth (usually the tile thickness): 9 mm
- Grout density: 1.2 kg/L
- Bag size: 5 kg
- Extra for waste: 10%
Find: 5 kg bags to buy
Answer
2.
Problem 2.
- Units: US (ft², inches, lb)
- Area to tile: 120 ft²
- Tile length: 10 in
- Tile width: 12 in
- Grout joint width: 0.1 in
- Joint depth (usually the tile thickness): 0.45 in
- Grout density (cured, as packed): 120 lb/ft³
- Bag size: 34 lb
- Extra for waste: 8%
Find: 34 lb bags to buy
Answer
3.
Problem 3.
- Units: Metric (m², mm, kg)
- Area to tile: 13 m²
- Tile length: 325 mm
- Tile width: 220 mm
- Grout joint width: 3 mm
- Joint depth (usually the tile thickness): 11 mm
- Grout density: 1.5 kg/L
- Bag size: 5 kg
- Extra for waste: 6%
Find: 5 kg bags to buy
Answer
4.
Problem 4.
- Units: Metric (m², mm, kg)
- Area to tile: 9 m²
- Tile length: 275 mm
- Tile width: 340 mm
- Grout joint width: 3 mm
- Joint depth (usually the tile thickness): 9 mm
- Grout density: 1.8 kg/L
- Bag size: 4 kg
- Extra for waste: 12%
Find: 4 kg bags to buy
Answer
5.
Problem 5.
- Units: Metric (m², mm, kg)
- Area to tile: 9 m²
- Tile length: 300 mm
- Tile width: 205 mm
- Grout joint width: 3 mm
- Joint depth (usually the tile thickness): 12 mm
- Grout density: 1.6 kg/L
- Bag size: 6 kg
- Extra for waste: 10%
Find: 6 kg bags to buy
Answer
6.
Problem 6.
- Units: US (ft², inches, lb)
- Area to tile: 120 ft²
- Tile length: 10 in
- Tile width: 13 in
- Grout joint width: 0.11 in
- Joint depth (usually the tile thickness): 0.34 in
- Grout density (cured, as packed): 85 lb/ft³
- Bag size: 22 lb
- Extra for waste: 9%
Find: 22 lb bags to buy
Answer
7.
Problem 7.
- Units: Metric (m², mm, kg)
- Area to tile: 8 m²
- Tile length: 300 mm
- Tile width: 300 mm
- Grout joint width: 2 mm
- Joint depth (usually the tile thickness): 8 mm
- Grout density: 0.9 kg/L
- Bag size: 6 kg
- Extra for waste: 11%
Find: 6 kg bags to buy
Answer
8.
Problem 8.
- Units: Metric (m², mm, kg)
- Area to tile: 10 m²
- Tile length: 200 mm
- Tile width: 240 mm
- Grout joint width: 4 mm
- Joint depth (usually the tile thickness): 9 mm
- Grout density: 1.8 kg/L
- Bag size: 5 kg
- Extra for waste: 12%
Find: 5 kg bags to buy
Answer
9.
Problem 9.
- Units: US (ft², inches, lb)
- Area to tile: 90 ft²
- Tile length: 13 in
- Tile width: 10 in
- Grout joint width: 0.095 in
- Joint depth (usually the tile thickness): 0.46 in
- Grout density (cured, as packed): 100 lb/ft³
- Bag size: 28 lb
- Extra for waste: 10%
Find: 28 lb bags to buy
Answer
10.
Problem 10.
- Units: Metric (m², mm, kg)
- Area to tile: 12 m²
- Tile length: 280 mm
- Tile width: 380 mm
- Grout joint width: 3 mm
- Joint depth (usually the tile thickness): 8 mm
- Grout density: 1.5 kg/L
- Bag size: 3 kg
- Extra for waste: 10%
Find: 3 kg bags to buy
Answer

Answer key: Grout worksheet

1. 5 kg bags to buy: 1
1. Find what share of the surface is joint: each tile brings one joint along its length and one along its width, compared with the tile's own area
  $\frac{(320 + 350) \times 2}{320 \times 350}$ $= 0.011964$
2. Find the grout volume: the joint area × the 9 mm depth. Handily, 1 m² × 1 mm is exactly 1 liter
  $10 \times 0.011964 \times 9$ $= 1.076786 L$
3. Turn the volume into weight using the grout's density (1.2 kg/L), then add 10% for waste
  $1.076786 \times 1.2 \times 1.1$ $= 1.4214 kg$
4. Divide by the 5 kg bag size and round up, since you can only buy whole bags
  $\frac{1.4214}{5}$ $= 0.2843$ $= rounded up: 1$
2. 34 lb bags to buy: 1
1. Find what share of the surface is joint: each tile brings one joint along its length and one along its width, compared with the tile's own area
  $\frac{(10 + 12) \times 0.1}{10 \times 12}$ $= 0.018333$
2. Find the grout volume: the joint area × the 0.45 in depth. Multiply by 144 to work in square inches, then divide by 1,728 to get cubic feet
  $\frac{120 \times 144 \times 0.018333 \times 0.45}{1,728}$ $= 0.0825 ft³$
3. Turn the volume into weight using the grout's density (120 lb/ft³), then add 8% for waste
  $0.0825 \times 120 \times 1.08$ $= 10.692 lb$
4. Divide by the 34 lb bag size and round up, since you can only buy whole bags
  $\frac{10.692}{34}$ $= 0.3145$ $= rounded up: 1$
3. 5 kg bags to buy: 2
1. Find what share of the surface is joint: each tile brings one joint along its length and one along its width, compared with the tile's own area
  $\frac{(325 + 220) \times 3}{325 \times 220}$ $= 0.022867$
2. Find the grout volume: the joint area × the 11 mm depth. Handily, 1 m² × 1 mm is exactly 1 liter
  $13 \times 0.022867 \times 11$ $= 3.27 L$
3. Turn the volume into weight using the grout's density (1.5 kg/L), then add 6% for waste
  $3.27 \times 1.5 \times 1.06$ $= 5.1993 kg$
4. Divide by the 5 kg bag size and round up, since you can only buy whole bags
  $\frac{5.1993}{5}$ $= 1.0399$ $= rounded up: 2$
4. 4 kg bags to buy: 1
1. Find what share of the surface is joint: each tile brings one joint along its length and one along its width, compared with the tile's own area
  $\frac{(275 + 340) \times 3}{275 \times 340}$ $= 0.019733$
2. Find the grout volume: the joint area × the 9 mm depth. Handily, 1 m² × 1 mm is exactly 1 liter
  $9 \times 0.019733 \times 9$ $= 1.598342 L$
3. Turn the volume into weight using the grout's density (1.8 kg/L), then add 12% for waste
  $1.598342 \times 1.8 \times 1.12$ $= 3.2223 kg$
4. Divide by the 4 kg bag size and round up, since you can only buy whole bags
  $\frac{3.2223}{4}$ $= 0.8056$ $= rounded up: 1$
5. 6 kg bags to buy: 1
1. Find what share of the surface is joint: each tile brings one joint along its length and one along its width, compared with the tile's own area
  $\frac{(300 + 205) \times 3}{300 \times 205}$ $= 0.024634$
2. Find the grout volume: the joint area × the 12 mm depth. Handily, 1 m² × 1 mm is exactly 1 liter
  $9 \times 0.024634 \times 12$ $= 2.660488 L$
3. Turn the volume into weight using the grout's density (1.6 kg/L), then add 10% for waste
  $2.660488 \times 1.6 \times 1.1$ $= 4.6825 kg$
4. Divide by the 6 kg bag size and round up, since you can only buy whole bags
  $\frac{4.6825}{6}$ $= 0.7804$ $= rounded up: 1$
6. 22 lb bags to buy: 1
1. Find what share of the surface is joint: each tile brings one joint along its length and one along its width, compared with the tile's own area
  $\frac{(10 + 13) \times 0.11}{10 \times 13}$ $= 0.019462$
2. Find the grout volume: the joint area × the 0.34 in depth. Multiply by 144 to work in square inches, then divide by 1,728 to get cubic feet
  $\frac{120 \times 144 \times 0.019462 \times 0.34}{1,728}$ $= 0.066169 ft³$
3. Turn the volume into weight using the grout's density (85 lb/ft³), then add 9% for waste
  $0.066169 \times 85 \times 1.09$ $= 6.1306 lb$
4. Divide by the 22 lb bag size and round up, since you can only buy whole bags
  $\frac{6.1306}{22}$ $= 0.2787$ $= rounded up: 1$
7. 6 kg bags to buy: 1
1. Find what share of the surface is joint: each tile brings one joint along its length and one along its width, compared with the tile's own area
  $\frac{(300 + 300) \times 2}{300 \times 300}$ $= 0.013333$
2. Find the grout volume: the joint area × the 8 mm depth. Handily, 1 m² × 1 mm is exactly 1 liter
  $8 \times 0.013333 \times 8$ $= 0.853333 L$
3. Turn the volume into weight using the grout's density (0.9 kg/L), then add 11% for waste
  $0.853333 \times 0.9 \times 1.11$ $= 0.8525 kg$
4. Divide by the 6 kg bag size and round up, since you can only buy whole bags
  $\frac{0.8525}{6}$ $= 0.1421$ $= rounded up: 1$
8. 5 kg bags to buy: 2
1. Find what share of the surface is joint: each tile brings one joint along its length and one along its width, compared with the tile's own area
  $\frac{(200 + 240) \times 4}{200 \times 240}$ $= 0.036667$
2. Find the grout volume: the joint area × the 9 mm depth. Handily, 1 m² × 1 mm is exactly 1 liter
  $10 \times 0.036667 \times 9$ $= 3.3 L$
3. Turn the volume into weight using the grout's density (1.8 kg/L), then add 12% for waste
  $3.3 \times 1.8 \times 1.12$ $= 6.6528 kg$
4. Divide by the 5 kg bag size and round up, since you can only buy whole bags
  $\frac{6.6528}{5}$ $= 1.3306$ $= rounded up: 2$
9. 28 lb bags to buy: 1
1. Find what share of the surface is joint: each tile brings one joint along its length and one along its width, compared with the tile's own area
  $\frac{(13 + 10) \times 0.095}{13 \times 10}$ $= 0.016808$
2. Find the grout volume: the joint area × the 0.46 in depth. Multiply by 144 to work in square inches, then divide by 1,728 to get cubic feet
  $\frac{90 \times 144 \times 0.016808 \times 0.46}{1,728}$ $= 0.057987 ft³$
3. Turn the volume into weight using the grout's density (100 lb/ft³), then add 10% for waste
  $0.057987 \times 100 \times 1.1$ $= 6.3785 lb$
4. Divide by the 28 lb bag size and round up, since you can only buy whole bags
  $\frac{6.3785}{28}$ $= 0.2278$ $= rounded up: 1$
10. 3 kg bags to buy: 1
1. Find what share of the surface is joint: each tile brings one joint along its length and one along its width, compared with the tile's own area
  $\frac{(280 + 380) \times 3}{280 \times 380}$ $= 0.018609$
2. Find the grout volume: the joint area × the 8 mm depth. Handily, 1 m² × 1 mm is exactly 1 liter
  $12 \times 0.018609 \times 8$ $= 1.786466 L$
3. Turn the volume into weight using the grout's density (1.5 kg/L), then add 10% for waste
  $1.786466 \times 1.5 \times 1.1$ $= 2.9477 kg$
4. Divide by the 3 kg bag size and round up, since you can only buy whole bags
  $\frac{2.9477}{3}$ $= 0.9826$ $= rounded up: 1$