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Paver worksheet

Grades 6–7 · CCSS 6.G.A.2, 6.RP.A.3.d

Solve each problem and show your work. Round answers to 2 decimal places where needed.

1.
Problem 1.
- Units: Metric (meters, mm, m³, tonnes)
- Paved area: Length × width
- Length: 5 m
- Width: 4 m
- Paver coverage: Pavers per unit area
- Pavers per square meter: 42 per m²
- Extra pavers for cuts and breakage: 7%
- Base gravel depth: 9 cm
- Bedding sand depth: 3 cm
- Extra base and sand for compaction: 10%
- Base gravel density: 1.6 t/m³
- Sand density: 1.9 t/m³
Find: Pavers to buy
Answer
2.
Problem 2.
- Units: US (feet, inches, yd³, tons)
- Paved area: Length × width
- Length: 12 ft
- Width: 8 ft
- Paver coverage: Paver size
- Paver length: 9 in
- Paver width: 5 in
- Extra pavers for cuts and breakage: 14%
- Base gravel depth: 3 in
- Bedding sand depth: 2 in
- Extra base and sand for compaction: 11%
- Base gravel density: 2,800 lb/yd³
- Sand density: 2,600 lb/yd³
Find: Pavers to buy
Answer
3.
Problem 3.
- Units: Metric (meters, mm, m³, tonnes)
- Paved area: Length × width
- Length: 4 m
- Width: 3 m
- Paver coverage: Pavers per unit area
- Pavers per square meter: 42 per m²
- Extra pavers for cuts and breakage: 8%
- Base gravel depth: 9 cm
- Bedding sand depth: 4 cm
- Extra base and sand for compaction: 9%
- Base gravel density: 2 t/m³
- Sand density: 1.4 t/m³
Find: Pavers to buy
Answer
4.
Problem 4.
- Units: Metric (meters, mm, m³, tonnes)
- Paved area: Length × width
- Length: 3 m
- Width: 4 m
- Paver coverage: Paver size
- Paver length: 200 mm
- Paver width: 75 mm
- Extra pavers for cuts and breakage: 10%
- Base gravel depth: 9 cm
- Bedding sand depth: 3 cm
- Extra base and sand for compaction: 11%
- Base gravel density: 1.6 t/m³
- Sand density: 1.3 t/m³
Find: Pavers to buy
Answer
5.
Problem 5.
- Units: US (feet, inches, yd³, tons)
- Paved area: Length × width
- Length: 14 ft
- Width: 10 ft
- Paver coverage: Paver size
- Paver length: 8 in
- Paver width: 4 in
- Extra pavers for cuts and breakage: 10%
- Base gravel depth: 2 in
- Bedding sand depth: 1 in
- Extra base and sand for compaction: 9%
- Base gravel density: 2,400 lb/yd³
- Sand density: 2,750 lb/yd³
Find: Pavers to buy
Answer
6.
Problem 6.
- Units: US (feet, inches, yd³, tons)
- Paved area: Length × width
- Length: 11 ft
- Width: 8 ft
- Paver coverage: Pavers per unit area
- Pavers per square foot: 3.3 per ft²
- Extra pavers for cuts and breakage: 11%
- Base gravel depth: 5 in
- Bedding sand depth: 1 in
- Extra base and sand for compaction: 10%
- Base gravel density: 2,450 lb/yd³
- Sand density: 3,000 lb/yd³
Find: Pavers to buy
Answer
7.
Problem 7.
- Units: US (feet, inches, yd³, tons)
- Paved area: Known area
- Area: 110 ft²
- Paver coverage: Paver size
- Paver length: 7 in
- Paver width: 4 in
- Extra pavers for cuts and breakage: 14%
- Base gravel depth: 4 in
- Bedding sand depth: 1 in
- Extra base and sand for compaction: 8%
- Base gravel density: 2,200 lb/yd³
- Sand density: 3,350 lb/yd³
Find: Pavers to buy
Answer
8.
Problem 8.
- Units: Metric (meters, mm, m³, tonnes)
- Paved area: Length × width
- Length: 4 m
- Width: 3 m
- Paver coverage: Pavers per unit area
- Pavers per square meter: 64 per m²
- Extra pavers for cuts and breakage: 11%
- Base gravel depth: 13 cm
- Bedding sand depth: 3 cm
- Extra base and sand for compaction: 10%
- Base gravel density: 1.8 t/m³
- Sand density: 1.3 t/m³
Find: Pavers to buy
Answer
9.
Problem 9.
- Units: US (feet, inches, yd³, tons)
- Paved area: Known area
- Area: 110 ft²
- Paver coverage: Paver size
- Paver length: 9 in
- Paver width: 4 in
- Extra pavers for cuts and breakage: 11%
- Base gravel depth: 5 in
- Bedding sand depth: 1 in
- Extra base and sand for compaction: 8%
- Base gravel density: 3,400 lb/yd³
- Sand density: 2,600 lb/yd³
Find: Pavers to buy
Answer
10.
Problem 10.
- Units: Metric (meters, mm, m³, tonnes)
- Paved area: Known area
- Area: 10 m²
- Paver coverage: Pavers per unit area
- Pavers per square meter: 44 per m²
- Extra pavers for cuts and breakage: 8%
- Base gravel depth: 9 cm
- Bedding sand depth: 2 cm
- Extra base and sand for compaction: 9%
- Base gravel density: 1.4 t/m³
- Sand density: 1.6 t/m³
Find: Pavers to buy
Answer

Answer key: Paver worksheet

1. Pavers to buy: 899 pavers
1. Multiply length by width to get the area you're paving
  $5 \times 4$ $= 20 m²$
2. Multiply the area by the pavers in each m² to get the pavers that fill it
  $20 \times 42$ $= 840$
3. Add 7% extra for cuts and breakage, then round up, since you can only buy whole pavers
  $840 \times 1 + 0.07$ $= 898.8$ $= rounded up: 899$
4. Base gravel: area × depth (cm ÷ 100 turns it into meters), plus extra because it shrinks when packed down
  $20 \times \frac{9}{100} \times 1 + 0.1$ $= 1.98 m³$
5. Base gravel weight: multiply the volume by how heavy each m³ is (its density)
  $1.98 \times 1.6$ $= 3.168 t$
6. Bedding sand: area × depth (cm ÷ 100 turns it into meters), plus extra because it shrinks when packed down
  $20 \times \frac{3}{100} \times 1 + 0.1$ $= 0.66 m³$
7. Bedding sand weight: multiply the volume by how heavy each m³ is (its density)
  $0.66 \times 1.9$ $= 1.254 t$
2. Pavers to buy: 351 pavers
1. Multiply length by width to get the area you're paving
  $12 \times 8$ $= 96 ft²$
2. Find how many pavers fit in one ft²: divide the 144 in² in it by the face of one paver (length × width)
  $\frac{144}{9 \times 5}$ $= 3.2 per ft²$
3. Multiply the area by the pavers in each ft² to get the pavers that fill it
  $96 \times 3.2$ $= 307.2$
4. Add 14% extra for cuts and breakage, then round up, since you can only buy whole pavers
  $307.2 \times 1 + 0.14$ $= 350.208$ $= rounded up: 351$
5. Base gravel: area × depth (in ÷ 12 turns it into feet), plus extra because it shrinks when packed down. Divide by 27 for cubic yards
  $\frac{96 \times \frac{3}{12} \times 1 + 0.11}{27}$ $= 0.986667 yd³$
6. Base gravel weight: multiply the volume by how heavy each yd³ is (its density), then divide by 2,000 lb per ton
  $\frac{0.986667 \times 2,800}{2,000}$ $= 1.381333 tons$
7. Bedding sand: area × depth (in ÷ 12 turns it into feet), plus extra because it shrinks when packed down. Divide by 27 for cubic yards
  $\frac{96 \times \frac{2}{12} \times 1 + 0.11}{27}$ $= 0.657778 yd³$
8. Bedding sand weight: multiply the volume by how heavy each yd³ is (its density), then divide by 2,000 lb per ton
  $\frac{0.657778 \times 2,600}{2,000}$ $= 0.855111 tons$
3. Pavers to buy: 545 pavers
1. Multiply length by width to get the area you're paving
  $4 \times 3$ $= 12 m²$
2. Multiply the area by the pavers in each m² to get the pavers that fill it
  $12 \times 42$ $= 504$
3. Add 8% extra for cuts and breakage, then round up, since you can only buy whole pavers
  $504 \times 1 + 0.08$ $= 544.32$ $= rounded up: 545$
4. Base gravel: area × depth (cm ÷ 100 turns it into meters), plus extra because it shrinks when packed down
  $12 \times \frac{9}{100} \times 1 + 0.09$ $= 1.1772 m³$
5. Base gravel weight: multiply the volume by how heavy each m³ is (its density)
  $1.1772 \times 2$ $= 2.3544 t$
6. Bedding sand: area × depth (cm ÷ 100 turns it into meters), plus extra because it shrinks when packed down
  $12 \times \frac{4}{100} \times 1 + 0.09$ $= 0.5232 m³$
7. Bedding sand weight: multiply the volume by how heavy each m³ is (its density)
  $0.5232 \times 1.4$ $= 0.73248 t$
4. Pavers to buy: 880 pavers
1. Multiply length by width to get the area you're paving
  $3 \times 4$ $= 12 m²$
2. Find how many pavers fit in one m²: divide the 1,000,000 mm² in it by the face of one paver (length × width)
  $\frac{1,000,000}{200 \times 75}$ $= 66.666667 per m²$
3. Multiply the area by the pavers in each m² to get the pavers that fill it
  $12 \times 66.666667$ $= 800$
4. Add 10% extra for cuts and breakage, then round up, since you can only buy whole pavers
  $800 \times 1 + 0.1$ $= 880$ $= rounded up: 880$
5. Base gravel: area × depth (cm ÷ 100 turns it into meters), plus extra because it shrinks when packed down
  $12 \times \frac{9}{100} \times 1 + 0.11$ $= 1.1988 m³$
6. Base gravel weight: multiply the volume by how heavy each m³ is (its density)
  $1.1988 \times 1.6$ $= 1.91808 t$
7. Bedding sand: area × depth (cm ÷ 100 turns it into meters), plus extra because it shrinks when packed down
  $12 \times \frac{3}{100} \times 1 + 0.11$ $= 0.3996 m³$
8. Bedding sand weight: multiply the volume by how heavy each m³ is (its density)
  $0.3996 \times 1.3$ $= 0.51948 t$
5. Pavers to buy: 693 pavers
1. Multiply length by width to get the area you're paving
  $14 \times 10$ $= 140 ft²$
2. Find how many pavers fit in one ft²: divide the 144 in² in it by the face of one paver (length × width)
  $\frac{144}{8 \times 4}$ $= 4.5 per ft²$
3. Multiply the area by the pavers in each ft² to get the pavers that fill it
  $140 \times 4.5$ $= 630$
4. Add 10% extra for cuts and breakage, then round up, since you can only buy whole pavers
  $630 \times 1 + 0.1$ $= 693$ $= rounded up: 693$
5. Base gravel: area × depth (in ÷ 12 turns it into feet), plus extra because it shrinks when packed down. Divide by 27 for cubic yards
  $\frac{140 \times \frac{2}{12} \times 1 + 0.09}{27}$ $= 0.941975 yd³$
6. Base gravel weight: multiply the volume by how heavy each yd³ is (its density), then divide by 2,000 lb per ton
  $\frac{0.941975 \times 2,400}{2,000}$ $= 1.13037 tons$
7. Bedding sand: area × depth (in ÷ 12 turns it into feet), plus extra because it shrinks when packed down. Divide by 27 for cubic yards
  $\frac{140 \times \frac{1}{12} \times 1 + 0.09}{27}$ $= 0.470988 yd³$
8. Bedding sand weight: multiply the volume by how heavy each yd³ is (its density), then divide by 2,000 lb per ton
  $\frac{0.470988 \times 2,750}{2,000}$ $= 0.647608 tons$
6. Pavers to buy: 323 pavers
1. Multiply length by width to get the area you're paving
  $11 \times 8$ $= 88 ft²$
2. Multiply the area by the pavers in each ft² to get the pavers that fill it
  $88 \times 3.3$ $= 290.4$
3. Add 11% extra for cuts and breakage, then round up, since you can only buy whole pavers
  $290.4 \times 1 + 0.11$ $= 322.344$ $= rounded up: 323$
4. Base gravel: area × depth (in ÷ 12 turns it into feet), plus extra because it shrinks when packed down. Divide by 27 for cubic yards
  $\frac{88 \times \frac{5}{12} \times 1 + 0.1}{27}$ $= 1.493827 yd³$
5. Base gravel weight: multiply the volume by how heavy each yd³ is (its density), then divide by 2,000 lb per ton
  $\frac{1.493827 \times 2,450}{2,000}$ $= 1.829938 tons$
6. Bedding sand: area × depth (in ÷ 12 turns it into feet), plus extra because it shrinks when packed down. Divide by 27 for cubic yards
  $\frac{88 \times \frac{1}{12} \times 1 + 0.1}{27}$ $= 0.298765 yd³$
7. Bedding sand weight: multiply the volume by how heavy each yd³ is (its density), then divide by 2,000 lb per ton
  $\frac{0.298765 \times 3,000}{2,000}$ $= 0.448148 tons$
7. Pavers to buy: 645 pavers
1. Find how many pavers fit in one ft²: divide the 144 in² in it by the face of one paver (length × width)
  $\frac{144}{7 \times 4}$ $= 5.142857 per ft²$
2. Multiply the area by the pavers in each ft² to get the pavers that fill it
  $110 \times 5.142857$ $= 565.714286$
3. Add 14% extra for cuts and breakage, then round up, since you can only buy whole pavers
  $565.714286 \times 1 + 0.14$ $= 644.9143$ $= rounded up: 645$
4. Base gravel: area × depth (in ÷ 12 turns it into feet), plus extra because it shrinks when packed down. Divide by 27 for cubic yards
  $\frac{110 \times \frac{4}{12} \times 1 + 0.08}{27}$ $= 1.466667 yd³$
5. Base gravel weight: multiply the volume by how heavy each yd³ is (its density), then divide by 2,000 lb per ton
  $\frac{1.466667 \times 2,200}{2,000}$ $= 1.613333 tons$
6. Bedding sand: area × depth (in ÷ 12 turns it into feet), plus extra because it shrinks when packed down. Divide by 27 for cubic yards
  $\frac{110 \times \frac{1}{12} \times 1 + 0.08}{27}$ $= 0.366667 yd³$
7. Bedding sand weight: multiply the volume by how heavy each yd³ is (its density), then divide by 2,000 lb per ton
  $\frac{0.366667 \times 3,350}{2,000}$ $= 0.614167 tons$
8. Pavers to buy: 853 pavers
1. Multiply length by width to get the area you're paving
  $4 \times 3$ $= 12 m²$
2. Multiply the area by the pavers in each m² to get the pavers that fill it
  $12 \times 64$ $= 768$
3. Add 11% extra for cuts and breakage, then round up, since you can only buy whole pavers
  $768 \times 1 + 0.11$ $= 852.48$ $= rounded up: 853$
4. Base gravel: area × depth (cm ÷ 100 turns it into meters), plus extra because it shrinks when packed down
  $12 \times \frac{13}{100} \times 1 + 0.1$ $= 1.716 m³$
5. Base gravel weight: multiply the volume by how heavy each m³ is (its density)
  $1.716 \times 1.8$ $= 3.0888 t$
6. Bedding sand: area × depth (cm ÷ 100 turns it into meters), plus extra because it shrinks when packed down
  $12 \times \frac{3}{100} \times 1 + 0.1$ $= 0.396 m³$
7. Bedding sand weight: multiply the volume by how heavy each m³ is (its density)
  $0.396 \times 1.3$ $= 0.5148 t$
9. Pavers to buy: 489 pavers
1. Find how many pavers fit in one ft²: divide the 144 in² in it by the face of one paver (length × width)
  $\frac{144}{9 \times 4}$ $= 4 per ft²$
2. Multiply the area by the pavers in each ft² to get the pavers that fill it
  $110 \times 4$ $= 440$
3. Add 11% extra for cuts and breakage, then round up, since you can only buy whole pavers
  $440 \times 1 + 0.11$ $= 488.4$ $= rounded up: 489$
4. Base gravel: area × depth (in ÷ 12 turns it into feet), plus extra because it shrinks when packed down. Divide by 27 for cubic yards
  $\frac{110 \times \frac{5}{12} \times 1 + 0.08}{27}$ $= 1.833333 yd³$
5. Base gravel weight: multiply the volume by how heavy each yd³ is (its density), then divide by 2,000 lb per ton
  $\frac{1.833333 \times 3,400}{2,000}$ $= 3.116667 tons$
6. Bedding sand: area × depth (in ÷ 12 turns it into feet), plus extra because it shrinks when packed down. Divide by 27 for cubic yards
  $\frac{110 \times \frac{1}{12} \times 1 + 0.08}{27}$ $= 0.366667 yd³$
7. Bedding sand weight: multiply the volume by how heavy each yd³ is (its density), then divide by 2,000 lb per ton
  $\frac{0.366667 \times 2,600}{2,000}$ $= 0.476667 tons$
10. Pavers to buy: 476 pavers
1. Multiply the area by the pavers in each m² to get the pavers that fill it
  $10 \times 44$ $= 440$
2. Add 8% extra for cuts and breakage, then round up, since you can only buy whole pavers
  $440 \times 1 + 0.08$ $= 475.2$ $= rounded up: 476$
3. Base gravel: area × depth (cm ÷ 100 turns it into meters), plus extra because it shrinks when packed down
  $10 \times \frac{9}{100} \times 1 + 0.09$ $= 0.981 m³$
4. Base gravel weight: multiply the volume by how heavy each m³ is (its density)
  $0.981 \times 1.4$ $= 1.3734 t$
5. Bedding sand: area × depth (cm ÷ 100 turns it into meters), plus extra because it shrinks when packed down
  $10 \times \frac{2}{100} \times 1 + 0.09$ $= 0.218 m³$
6. Bedding sand weight: multiply the volume by how heavy each m³ is (its density)
  $0.218 \times 1.6$ $= 0.3488 t$