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Percent Yield worksheet

Grades 10–11

Solve each problem and show your work. Round answers to 2 decimal places where needed.

1.
Problem 1.
- Calculate: Theoretical yield from the limiting reactant
- Moles of limiting reactant: 0.5 mol
- Coefficient of the limiting reactant: 2
- Coefficient of the product: 3
- Molar mass of the product: 14 g/mol
Find: Theoretical yield
Answer
2.
Problem 2.
- Calculate: Percent yield
- Actual yield: 7
- Theoretical yield: 7.5
Find: Percent yield
Answer
3.
Problem 3.
- Calculate: Percent yield
- Actual yield: 7
- Theoretical yield: 9
Find: Percent yield
Answer
4.
Problem 4.
- Calculate: Actual yield from a percent yield
- Percent yield: 70%
- Theoretical yield: 7
Find: Actual yield
Answer
5.
Problem 5.
- Calculate: Theoretical yield from the limiting reactant
- Moles of limiting reactant: 0.3 mol
- Coefficient of the limiting reactant: 3
- Coefficient of the product: 2
- Molar mass of the product: 25 g/mol
Find: Theoretical yield
Answer
6.
Problem 6.
- Calculate: Actual yield from a percent yield
- Percent yield: 68%
- Theoretical yield: 12
Find: Actual yield
Answer
7.
Problem 7.
- Calculate: Percent yield
- Actual yield: 8
- Theoretical yield: 6.5
Find: Percent yield
Answer
8.
Problem 8.
- Calculate: Percent yield
- Actual yield: 7.8
- Theoretical yield: 10.5
Find: Percent yield
Answer
9.
Problem 9.
- Calculate: Percent yield
- Actual yield: 7
- Theoretical yield: 7.4
Find: Percent yield
Answer
10.
Problem 10.
- Calculate: Percent yield
- Actual yield: 7.6
- Theoretical yield: 8
Find: Percent yield
Answer

Answer key: Percent Yield worksheet

1. Theoretical yield: 10.5 g
1. Scale the reactant's moles by the ratio of the numbers in front of product and reactant, because the equation says how many moles of each take part
  $0.5 mol \times \frac{3}{2}$ $= 0.75 mol$
2. Multiply the moles of product by its molar mass (grams per mole) to turn moles into grams
  $0.75 mol \times 14 g/mol$ $= 10.5 g$
2. Percent yield: 93.33%
1. Divide what you recovered by the most you could have made, then multiply by 100 to get a percent
  $percent yield$ $= \frac{7}{7.5} \times 100$ $= 93.333333%$
3. Percent yield: 77.78%
1. Divide what you recovered by the most you could have made, then multiply by 100 to get a percent
  $percent yield$ $= \frac{7}{9} \times 100$ $= 77.777778%$
4. Actual yield: 4.9
1. Multiply the theoretical yield by the percent yield as a decimal, since that share of the maximum is what you can expect to recover
  $actual$ $= \frac{70%}{100} \times 7$ $= 4.9$
5. Theoretical yield: 5 g
1. Scale the reactant's moles by the ratio of the numbers in front of product and reactant, because the equation says how many moles of each take part
  $0.3 mol \times \frac{2}{3}$ $= 0.2 mol$
2. Multiply the moles of product by its molar mass (grams per mole) to turn moles into grams
  $0.2 mol \times 25 g/mol$ $= 5 g$
6. Actual yield: 8.16
1. Multiply the theoretical yield by the percent yield as a decimal, since that share of the maximum is what you can expect to recover
  $actual$ $= \frac{68%}{100} \times 12$ $= 8.16$
7. Percent yield: 123.08%
1. Divide what you recovered by the most you could have made, then multiply by 100 to get a percent
  $percent yield$ $= \frac{8}{6.5} \times 100$ $= 123.076923%$
8. Percent yield: 74.29%
1. Divide what you recovered by the most you could have made, then multiply by 100 to get a percent
  $percent yield$ $= \frac{7.8}{10.5} \times 100$ $= 74.285714%$
9. Percent yield: 94.59%
1. Divide what you recovered by the most you could have made, then multiply by 100 to get a percent
  $percent yield$ $= \frac{7}{7.4} \times 100$ $= 94.594595%$
10. Percent yield: 95%
1. Divide what you recovered by the most you could have made, then multiply by 100 to get a percent
  $percent yield$ $= \frac{7.6}{8} \times 100$ $= 95%$