Pool Chlorine worksheet

1. Product to add (by weight): 19.4 oz

1. Turn gallons into liters, because chlorine levels are measured per liter (1 US gal = 3.785411784 L)

   $\mathrm{10,000}\text{\hspace{0.17em}gal}\times 3.785411784$$=\mathrm{37,854.12}\text{\hspace{0.17em}L}$

2. Subtract your current reading from the target to see how much to raise it

   $10-1$$=9\text{\hspace{0.17em}ppm}$

3. Find the grams of chlorine needed: 1 ppm is 1 mg in each liter, and 1,000 mg make a gram

   $\frac{9\times \mathrm{37,854.12}}{\mathrm{1,000}}$$=340.687\text{\hspace{0.17em}g}$

4. Divide by the label strength (62%), since only that share of the product is chlorine

   $\frac{340.687}{0.62}$$=549.5\text{\hspace{0.17em}g}$

5. Turn grams into ounces by weight so you can measure it (1 oz = 28.3495 g)

   $\frac{549.5}{28.3495}$$=19.38\text{\hspace{0.17em}oz}$

6. Stabilized products also add cyanuric acid (CYA), a set amount for each ppm of chlorine

   $9\times 0.91$$=8.19\text{\hspace{0.17em}ppm CYA}$

2. Product to add (by weight): 9.1 oz

1. Turn gallons into liters, because chlorine levels are measured per liter (1 US gal = 3.785411784 L)

   $\mathrm{20,000}\text{\hspace{0.17em}gal}\times 3.785411784$$=\mathrm{75,708.24}\text{\hspace{0.17em}L}$

2. Subtract your current reading from the target to see how much to raise it

   $4-1.5$$=2.5\text{\hspace{0.17em}ppm}$

3. Find the grams of chlorine needed: 1 ppm is 1 mg in each liter, and 1,000 mg make a gram

   $\frac{2.5\times \mathrm{75,708.24}}{\mathrm{1,000}}$$=189.271\text{\hspace{0.17em}g}$

4. Divide by the label strength (73%), since only that share of the product is chlorine

   $\frac{189.271}{0.73}$$=259.27\text{\hspace{0.17em}g}$

5. Turn grams into ounces by weight so you can measure it (1 oz = 28.3495 g)

   $\frac{259.27}{28.3495}$$=9.15\text{\hspace{0.17em}oz}$

6. Cal-hypo also adds calcium, which raises calcium hardness (counted as CaCO₃, as test kits do)

   $2.5\times 0.706$$=1.76\text{\hspace{0.17em}ppm CH}$

3. Product to add (by weight): 14.8 oz

1. Turn gallons into liters, because chlorine levels are measured per liter (1 US gal = 3.785411784 L)

   $\mathrm{18,000}\text{\hspace{0.17em}gal}\times 3.785411784$$=\mathrm{68,137.41}\text{\hspace{0.17em}L}$

2. Subtract your current reading from the target to see how much to raise it

   $4-0$$=4\text{\hspace{0.17em}ppm}$

3. Find the grams of chlorine needed: 1 ppm is 1 mg in each liter, and 1,000 mg make a gram

   $\frac{4\times \mathrm{68,137.41}}{\mathrm{1,000}}$$=272.55\text{\hspace{0.17em}g}$

4. Divide by the label strength (65%), since only that share of the product is chlorine

   $\frac{272.55}{0.65}$$=419.31\text{\hspace{0.17em}g}$

5. Turn grams into ounces by weight so you can measure it (1 oz = 28.3495 g)

   $\frac{419.31}{28.3495}$$=14.79\text{\hspace{0.17em}oz}$

6. Cal-hypo also adds calcium, which raises calcium hardness (counted as CaCO₃, as test kits do)

   $4\times 0.706$$=2.82\text{\hspace{0.17em}ppm CH}$

4. Liquid chlorine to add: 73.7 fl oz

1. Turn gallons into liters, because chlorine levels are measured per liter (1 US gal = 3.785411784 L)

   $\mathrm{18,000}\text{\hspace{0.17em}gal}\times 3.785411784$$=\mathrm{68,137.41}\text{\hspace{0.17em}L}$

2. Subtract your current reading from the target to see how much to raise it

   $4-0$$=4\text{\hspace{0.17em}ppm}$

3. Find the grams of chlorine needed: 1 ppm is 1 mg in each liter, and 1,000 mg make a gram

   $\frac{4\times \mathrm{68,137.41}}{\mathrm{1,000}}$$=272.55\text{\hspace{0.17em}g}$

4. Divide by the label strength to get how much liquid to pour (12.5% means 12.5 g of chlorine in each 100 mL)

   $\frac{272.55}{0.125}$$=\mathrm{2,180.4}\text{\hspace{0.17em}mL}$

5. Turn milliliters into US fluid ounces so you can measure it (1 fl oz = 29.5735 mL)

   $\frac{\mathrm{2,180.4}}{29.5735}$$=73.73\text{\hspace{0.17em}fl oz}$

5. Product to add (by weight): 11.8 oz

1. Turn gallons into liters, because chlorine levels are measured per liter (1 US gal = 3.785411784 L)

   $\mathrm{15,000}\text{\hspace{0.17em}gal}\times 3.785411784$$=\mathrm{56,781.18}\text{\hspace{0.17em}L}$

2. Subtract your current reading from the target to see how much to raise it

   $4-0$$=4\text{\hspace{0.17em}ppm}$

3. Find the grams of chlorine needed: 1 ppm is 1 mg in each liter, and 1,000 mg make a gram

   $\frac{4\times \mathrm{56,781.18}}{\mathrm{1,000}}$$=227.125\text{\hspace{0.17em}g}$

4. Divide by the label strength (68%), since only that share of the product is chlorine

   $\frac{227.125}{0.68}$$=334.01\text{\hspace{0.17em}g}$

5. Turn grams into ounces by weight so you can measure it (1 oz = 28.3495 g)

   $\frac{334.01}{28.3495}$$=11.78\text{\hspace{0.17em}oz}$

6. Cal-hypo also adds calcium, which raises calcium hardness (counted as CaCO₃, as test kits do)

   $4\times 0.706$$=2.82\text{\hspace{0.17em}ppm CH}$

6. Product to add (by weight): 10 oz

1. Turn gallons into liters, because chlorine levels are measured per liter (1 US gal = 3.785411784 L)

   $\mathrm{15,000}\text{\hspace{0.17em}gal}\times 3.785411784$$=\mathrm{56,781.18}\text{\hspace{0.17em}L}$

2. Subtract your current reading from the target to see how much to raise it

   $5-0.5$$=4.5\text{\hspace{0.17em}ppm}$

3. Find the grams of chlorine needed: 1 ppm is 1 mg in each liter, and 1,000 mg make a gram

   $\frac{4.5\times \mathrm{56,781.18}}{\mathrm{1,000}}$$=255.515\text{\hspace{0.17em}g}$

4. Divide by the label strength (90%), since only that share of the product is chlorine

   $\frac{255.515}{0.9}$$=283.91\text{\hspace{0.17em}g}$

5. Turn grams into ounces by weight so you can measure it (1 oz = 28.3495 g)

   $\frac{283.91}{28.3495}$$=10.01\text{\hspace{0.17em}oz}$

6. Stabilized products also add cyanuric acid (CYA), a set amount for each ppm of chlorine

   $4.5\times 0.607$$=2.73\text{\hspace{0.17em}ppm CYA}$

7. Product to add (by weight): 5.6 oz

1. Turn gallons into liters, because chlorine levels are measured per liter (1 US gal = 3.785411784 L)

   $\mathrm{15,000}\text{\hspace{0.17em}gal}\times 3.785411784$$=\mathrm{56,781.18}\text{\hspace{0.17em}L}$

2. Subtract your current reading from the target to see how much to raise it

   $4-1.5$$=2.5\text{\hspace{0.17em}ppm}$

3. Find the grams of chlorine needed: 1 ppm is 1 mg in each liter, and 1,000 mg make a gram

   $\frac{2.5\times \mathrm{56,781.18}}{\mathrm{1,000}}$$=141.953\text{\hspace{0.17em}g}$

4. Divide by the label strength (90%), since only that share of the product is chlorine

   $\frac{141.953}{0.9}$$=157.73\text{\hspace{0.17em}g}$

5. Turn grams into ounces by weight so you can measure it (1 oz = 28.3495 g)

   $\frac{157.73}{28.3495}$$=5.56\text{\hspace{0.17em}oz}$

6. Stabilized products also add cyanuric acid (CYA), a set amount for each ppm of chlorine

   $2.5\times 0.607$$=1.52\text{\hspace{0.17em}ppm CYA}$

8. Product to add (by weight): 3.3 oz

1. Turn gallons into liters, because chlorine levels are measured per liter (1 US gal = 3.785411784 L)

   $\mathrm{15,000}\text{\hspace{0.17em}gal}\times 3.785411784$$=\mathrm{56,781.18}\text{\hspace{0.17em}L}$

2. Subtract your current reading from the target to see how much to raise it

   $3-1.5$$=1.5\text{\hspace{0.17em}ppm}$

3. Find the grams of chlorine needed: 1 ppm is 1 mg in each liter, and 1,000 mg make a gram

   $\frac{1.5\times \mathrm{56,781.18}}{\mathrm{1,000}}$$=85.172\text{\hspace{0.17em}g}$

4. Divide by the label strength (90%), since only that share of the product is chlorine

   $\frac{85.172}{0.9}$$=94.64\text{\hspace{0.17em}g}$

5. Turn grams into ounces by weight so you can measure it (1 oz = 28.3495 g)

   $\frac{94.64}{28.3495}$$=3.34\text{\hspace{0.17em}oz}$

6. Stabilized products also add cyanuric acid (CYA), a set amount for each ppm of chlorine

   $1.5\times 0.607$$=0.91\text{\hspace{0.17em}ppm CYA}$

9. Product to add (by weight): 14.7 oz

1. Turn gallons into liters, because chlorine levels are measured per liter (1 US gal = 3.785411784 L)

   $\mathrm{15,000}\text{\hspace{0.17em}gal}\times 3.785411784$$=\mathrm{56,781.18}\text{\hspace{0.17em}L}$

2. Subtract your current reading from the target to see how much to raise it

   $5-0$$=5\text{\hspace{0.17em}ppm}$

3. Find the grams of chlorine needed: 1 ppm is 1 mg in each liter, and 1,000 mg make a gram

   $\frac{5\times \mathrm{56,781.18}}{\mathrm{1,000}}$$=283.906\text{\hspace{0.17em}g}$

4. Divide by the label strength (68%), since only that share of the product is chlorine

   $\frac{283.906}{0.68}$$=417.51\text{\hspace{0.17em}g}$

5. Turn grams into ounces by weight so you can measure it (1 oz = 28.3495 g)

   $\frac{417.51}{28.3495}$$=14.73\text{\hspace{0.17em}oz}$

6. Cal-hypo also adds calcium, which raises calcium hardness (counted as CaCO₃, as test kits do)

   $5\times 0.706$$=3.53\text{\hspace{0.17em}ppm CH}$

10. Liquid chlorine to add: 76.8 fl oz

1. Turn gallons into liters, because chlorine levels are measured per liter (1 US gal = 3.785411784 L)

   $\mathrm{15,000}\text{\hspace{0.17em}gal}\times 3.785411784$$=\mathrm{56,781.18}\text{\hspace{0.17em}L}$

2. Subtract your current reading from the target to see how much to raise it

   $5-0$$=5\text{\hspace{0.17em}ppm}$

3. Find the grams of chlorine needed: 1 ppm is 1 mg in each liter, and 1,000 mg make a gram

   $\frac{5\times \mathrm{56,781.18}}{\mathrm{1,000}}$$=283.906\text{\hspace{0.17em}g}$

4. Divide by the label strength to get how much liquid to pour (12.5% means 12.5 g of chlorine in each 100 mL)

   $\frac{283.906}{0.125}$$=\mathrm{2,271.25}\text{\hspace{0.17em}mL}$

5. Turn milliliters into US fluid ounces so you can measure it (1 fl oz = 29.5735 mL)

   $\frac{\mathrm{2,271.25}}{29.5735}$$=76.8\text{\hspace{0.17em}fl oz}$