Rebar worksheet

1. Total rebar length (with laps and waste): 768.1 m

1. Count the lengthwise bars: take the slab width minus both edge gaps, divide by the spacing and round down. Add 1, since a row has one more bar than gaps

   $\frac{\left(7-2\times 0.06\right)}{0.26}+1$$=\text{rounded down:}27$

2. Count the widthwise bars the same way, using the slab length minus both edge gaps

   $\frac{\left(13-2\times 0.06\right)}{0.26}+1$$=\text{rounded down:}50$

3. Each run lengthwise is longer than a stock bar, so it takes 3 pieces joined by 2 laps. Each overlap adds its length to the steel needed

   $12.88+2\times 0.45$$=13.78\text{\hspace{0.17em}m}$

4. Each run widthwise is longer than a stock bar, so it takes 2 pieces joined by 1 lap. Each overlap adds its length to the steel needed

   $6.88+1\times 0.45$$=7.33\text{\hspace{0.17em}m}$

5. Add up the steel in the grid: number of bars times length per bar, in each direction

   $27\times 13.78+50\times 7.33$$=738.56\text{\hspace{0.17em}m}$

6. Add 4% for offcuts too short to reuse

   $738.56\times 1+0.04$$=768.1024\text{\hspace{0.17em}m}$

7. Divide the total by the 6 m stock length and round up, since you can only buy whole bars

   $\frac{768.1024}{6}$$=128.0171$$=\text{rounded up:}129$

8. Multiply the total length by 0.5595 kg/m, the standard listed weight of #3 bar

   $768.1024\times 0.55955$$=429.791424\text{\hspace{0.17em}kg}$

2. Total rebar length (with laps and waste): 495.62 m

1. Count the lengthwise bars: take the slab width minus both edge gaps, divide by the spacing and round down. Add 1, since a row has one more bar than gaps

   $\frac{\left(5-2\times 0.062\right)}{0.24}+1$$=\text{rounded down:}21$

2. Count the widthwise bars the same way, using the slab length minus both edge gaps

   $\frac{\left(11-2\times 0.062\right)}{0.24}+1$$=\text{rounded down:}46$

3. Each run lengthwise is longer than a stock bar, so it takes 2 pieces joined by 1 lap. Each overlap adds its length to the steel needed

   $10.876+1\times 0.5$$=11.376\text{\hspace{0.17em}m}$

4. Each bar widthwise is 4.876 m, which fits in one 7 m stock bar with no splice

   $5-2\times 0.062$$=4.876\text{\hspace{0.17em}m}$

5. Add up the steel in the grid: number of bars times length per bar, in each direction

   $21\times 11.376+46\times 4.876$$=463.192\text{\hspace{0.17em}m}$

6. Add 7% for offcuts too short to reuse

   $463.192\times 1+0.07$$=495.61544\text{\hspace{0.17em}m}$

7. Divide the total by the 7 m stock length and round up, since you can only buy whole bars

   $\frac{495.61544}{7}$$=70.8022$$=\text{rounded up:}71$

8. Multiply the total length by 0.9941 kg/m, the standard listed weight of #4 bar

   $495.61544\times 0.994094$$=492.688094\text{\hspace{0.17em}kg}$

3. Total rebar length (with laps and waste): 416.73 m

1. Count the lengthwise bars: take the slab width minus both edge gaps, divide by the spacing and round down. Add 1, since a row has one more bar than gaps

   $\frac{\left(8-2\times 0.076\right)}{0.34}+1$$=\text{rounded down:}24$

2. Count the widthwise bars the same way, using the slab length minus both edge gaps

   $\frac{\left(8-2\times 0.076\right)}{0.34}+1$$=\text{rounded down:}24$

3. Each run lengthwise is longer than a stock bar, so it takes 2 pieces joined by 1 lap. Each overlap adds its length to the steel needed

   $7.848+1\times 0.5$$=8.348\text{\hspace{0.17em}m}$

4. Each run widthwise is longer than a stock bar, so it takes 2 pieces joined by 1 lap. Each overlap adds its length to the steel needed

   $7.848+1\times 0.5$$=8.348\text{\hspace{0.17em}m}$

5. Add up the steel in the grid: number of bars times length per bar, in each direction

   $24\times 8.348+24\times 8.348$$=400.704\text{\hspace{0.17em}m}$

6. Add 4% for offcuts too short to reuse

   $400.704\times 1+0.04$$=416.73216\text{\hspace{0.17em}m}$

7. Divide the total by the 6 m stock length and round up, since you can only buy whole bars

   $\frac{416.73216}{6}$$=69.4554$$=\text{rounded up:}70$

8. Multiply the total length by 3.9734 kg/m, the standard listed weight of #8 bar

   $416.73216\times 3.973398$$=\mathrm{1,655.842618}\text{\hspace{0.17em}kg}$

4. Total rebar length (with laps and waste): 888.83 ft

1. Count the lengthwise bars: take the slab width minus both edge gaps, divide by the spacing and round down. Add 1, since a row has one more bar than gaps

   $\frac{\left(13-2\times 0.25\right)}{0.916667}+1$$=\text{rounded down:}14$

2. Count the widthwise bars the same way, using the slab length minus both edge gaps

   $\frac{\left(30-2\times 0.25\right)}{0.916667}+1$$=\text{rounded down:}33$

3. Each run lengthwise is longer than a stock bar, so it takes 2 pieces joined by 1 lap. Each overlap adds its length to the steel needed

   $29.5+1\times 1.5$$=31\text{\hspace{0.17em}ft}$

4. Each bar widthwise is 12.5 ft, which fits in one 23 ft stock bar with no splice

   $13-2\times 0.25$$=12.5\text{\hspace{0.17em}ft}$

5. Add up the steel in the grid: number of bars times length per bar, in each direction

   $14\times 31+33\times 12.5$$=846.5\text{\hspace{0.17em}ft}$

6. Add 5% for offcuts too short to reuse

   $846.5\times 1+0.05$$=888.825\text{\hspace{0.17em}ft}$

7. Divide the total by the 23 ft stock length and round up, since you can only buy whole bars

   $\frac{888.825}{23}$$=38.6446$$=\text{rounded up:}39$

8. Multiply the total length by 0.376 lb/ft, the standard listed weight of #3 bar

   $888.825\times 0.376$$=334.1982\text{\hspace{0.17em}lb}$

5. Total rebar length (with laps and waste): 217.4 m

1. Count the lengthwise bars: take the slab width minus both edge gaps, divide by the spacing and round down. Add 1, since a row has one more bar than gaps

   $\frac{\left(7-2\times 0.06\right)}{0.4}+1$$=\text{rounded down:}18$

2. Count the widthwise bars the same way, using the slab length minus both edge gaps

   $\frac{\left(6-2\times 0.06\right)}{0.4}+1$$=\text{rounded down:}15$

3. Each bar lengthwise is 5.88 m, which fits in one 8 m stock bar with no splice

   $6-2\times 0.06$$=5.88\text{\hspace{0.17em}m}$

4. Each bar widthwise is 6.88 m, which fits in one 8 m stock bar with no splice

   $7-2\times 0.06$$=6.88\text{\hspace{0.17em}m}$

5. Add up the steel in the grid: number of bars times length per bar, in each direction

   $18\times 5.88+15\times 6.88$$=209.04\text{\hspace{0.17em}m}$

6. Add 4% for offcuts too short to reuse

   $209.04\times 1+0.04$$=217.4016\text{\hspace{0.17em}m}$

7. Divide the total by the 8 m stock length and round up, since you can only buy whole bars

   $\frac{217.4016}{8}$$=27.1752$$=\text{rounded up:}28$

8. Multiply the total length by 3.0418 kg/m, the standard listed weight of #7 bar

   $217.4016\times 3.041807$$=661.293731\text{\hspace{0.17em}kg}$

6. Total rebar length (with laps and waste): 1,629.68 ft

1. Count the lengthwise bars: take the slab width minus both edge gaps, divide by the spacing and round down. Add 1, since a row has one more bar than gaps

   $\frac{\left(20-2\times 0.166667\right)}{0.833333}+1$$=\text{rounded down:}24$

2. Count the widthwise bars the same way, using the slab length minus both edge gaps

   $\frac{\left(32-2\times 0.166667\right)}{0.833333}+1$$=\text{rounded down:}39$

3. Each run lengthwise is longer than a stock bar, so it takes 2 pieces joined by 1 lap. Each overlap adds its length to the steel needed

   $31.666667+1\times 1.666667$$=33.333333\text{\hspace{0.17em}ft}$

4. Each bar widthwise is 19.6667 ft, which fits in one 20 ft stock bar with no splice

   $20-2\times 0.166667$$=19.666667\text{\hspace{0.17em}ft}$

5. Add up the steel in the grid: number of bars times length per bar, in each direction

   $24\times 33.333333+39\times 19.666667$$=\mathrm{1,567}\text{\hspace{0.17em}ft}$

6. Add 4% for offcuts too short to reuse

   $\mathrm{1,567}\times 1+0.04$$=\mathrm{1,629.68}\text{\hspace{0.17em}ft}$

7. Divide the total by the 20 ft stock length and round up, since you can only buy whole bars

   $\frac{\mathrm{1,629.68}}{20}$$=81.484$$=\text{rounded up:}82$

8. Multiply the total length by 2.67 lb/ft, the standard listed weight of #8 bar

   $\mathrm{1,629.68}\times 2.67$$=\mathrm{4,351.2456}\text{\hspace{0.17em}lb}$

7. Total rebar length (with laps and waste): 1,108.29 ft

1. Count the lengthwise bars: take the slab width minus both edge gaps, divide by the spacing and round down. Add 1, since a row has one more bar than gaps

   $\frac{\left(17-2\times 0.25\right)}{0.916667}+1$$=\text{rounded down:}19$

2. Count the widthwise bars the same way, using the slab length minus both edge gaps

   $\frac{\left(28-2\times 0.25\right)}{0.916667}+1$$=\text{rounded down:}31$

3. Each run lengthwise is longer than a stock bar, so it takes 2 pieces joined by 1 lap. Each overlap adds its length to the steel needed

   $27.5+1\times 1.666667$$=29.166667\text{\hspace{0.17em}ft}$

4. Each bar widthwise is 16.5 ft, which fits in one 23 ft stock bar with no splice

   $17-2\times 0.25$$=16.5\text{\hspace{0.17em}ft}$

5. Add up the steel in the grid: number of bars times length per bar, in each direction

   $19\times 29.166667+31\times 16.5$$=\mathrm{1,065.666667}\text{\hspace{0.17em}ft}$

6. Add 4% for offcuts too short to reuse

   $\mathrm{1,065.666667}\times 1+0.04$$=\mathrm{1,108.293333}\text{\hspace{0.17em}ft}$

7. Divide the total by the 23 ft stock length and round up, since you can only buy whole bars

   $\frac{\mathrm{1,108.293333}}{23}$$=48.1867$$=\text{rounded up:}49$

8. Multiply the total length by 2.044 lb/ft, the standard listed weight of #7 bar

   $\mathrm{1,108.293333}\times 2.044$$=\mathrm{2,265.351573}\text{\hspace{0.17em}lb}$

8. Total rebar length (with laps and waste): 420.55 m

1. Count the lengthwise bars: take the slab width minus both edge gaps, divide by the spacing and round down. Add 1, since a row has one more bar than gaps

   $\frac{\left(6-2\times 0.09\right)}{0.2}+1$$=\text{rounded down:}30$

2. Count the widthwise bars the same way, using the slab length minus both edge gaps

   $\frac{\left(7-2\times 0.09\right)}{0.2}+1$$=\text{rounded down:}35$

3. Each bar lengthwise is 6.82 m, which fits in one 7 m stock bar with no splice

   $7-2\times 0.09$$=6.82\text{\hspace{0.17em}m}$

4. Each bar widthwise is 5.82 m, which fits in one 7 m stock bar with no splice

   $6-2\times 0.09$$=5.82\text{\hspace{0.17em}m}$

5. Add up the steel in the grid: number of bars times length per bar, in each direction

   $30\times 6.82+35\times 5.82$$=408.3\text{\hspace{0.17em}m}$

6. Add 3% for offcuts too short to reuse

   $408.3\times 1+0.03$$=420.549\text{\hspace{0.17em}m}$

7. Divide the total by the 7 m stock length and round up, since you can only buy whole bars

   $\frac{420.549}{7}$$=60.0784$$=\text{rounded up:}61$

8. Multiply the total length by 2.2352 kg/m, the standard listed weight of #6 bar

   $420.549\times 2.235222$$=940.020479\text{\hspace{0.17em}kg}$

9. Total rebar length (with laps and waste): 1,074.67 ft

1. Count the lengthwise bars: take the slab width minus both edge gaps, divide by the spacing and round down. Add 1, since a row has one more bar than gaps

   $\frac{\left(18-2\times 0.166667\right)}{1.166667}+1$$=\text{rounded down:}16$

2. Count the widthwise bars the same way, using the slab length minus both edge gaps

   $\frac{\left(32-2\times 0.166667\right)}{1.166667}+1$$=\text{rounded down:}28$

3. Each run lengthwise is longer than a stock bar, so it takes 2 pieces joined by 1 lap. Each overlap adds its length to the steel needed

   $31.666667+1\times 2$$=33.666667\text{\hspace{0.17em}ft}$

4. Each bar widthwise is 17.6667 ft, which fits in one 24 ft stock bar with no splice

   $18-2\times 0.166667$$=17.666667\text{\hspace{0.17em}ft}$

5. Add up the steel in the grid: number of bars times length per bar, in each direction

   $16\times 33.666667+28\times 17.666667$$=\mathrm{1,033.333333}\text{\hspace{0.17em}ft}$

6. Add 4% for offcuts too short to reuse

   $\mathrm{1,033.333333}\times 1+0.04$$=\mathrm{1,074.666667}\text{\hspace{0.17em}ft}$

7. Divide the total by the 24 ft stock length and round up, since you can only buy whole bars

   $\frac{\mathrm{1,074.666667}}{24}$$=44.7778$$=\text{rounded up:}45$

8. Multiply the total length by 0.376 lb/ft, the standard listed weight of #3 bar

   $\mathrm{1,074.666667}\times 0.376$$=404.074667\text{\hspace{0.17em}lb}$

10. Total rebar length (with laps and waste): 268.93 m

1. Count the lengthwise bars: take the slab width minus both edge gaps, divide by the spacing and round down. Add 1, since a row has one more bar than gaps

   $\frac{\left(5-2\times 0.055\right)}{0.36}+1$$=\text{rounded down:}14$

2. Count the widthwise bars the same way, using the slab length minus both edge gaps

   $\frac{\left(9-2\times 0.055\right)}{0.36}+1$$=\text{rounded down:}25$

3. Each run lengthwise is longer than a stock bar, so it takes 2 pieces joined by 1 lap. Each overlap adds its length to the steel needed

   $8.89+1\times 0.5$$=9.39\text{\hspace{0.17em}m}$

4. Each bar widthwise is 4.89 m, which fits in one 7 m stock bar with no splice

   $5-2\times 0.055$$=4.89\text{\hspace{0.17em}m}$

5. Add up the steel in the grid: number of bars times length per bar, in each direction

   $14\times 9.39+25\times 4.89$$=253.71\text{\hspace{0.17em}m}$

6. Add 6% for offcuts too short to reuse

   $253.71\times 1+0.06$$=268.9326\text{\hspace{0.17em}m}$

7. Divide the total by the 7 m stock length and round up, since you can only buy whole bars

   $\frac{268.9326}{7}$$=38.4189$$=\text{rounded up:}39$

8. Multiply the total length by 0.5595 kg/m, the standard listed weight of #3 bar

   $268.9326\times 0.55955$$=150.48114\text{\hspace{0.17em}kg}$