Printable worksheet

← Back to the Sand Calculator

In the print window, choose “Save as PDF” as the printer (or print it on paper). Seed 1 rebuilds this exact sheet.

Sand worksheet

Grades 6–7 · CCSS 6.G.A.2, 6.RP.A.3.d, 7.G.B.4

Solve each problem and show your work. Round answers to 2 decimal places where needed.

1.
Problem 1.
- Units: Metric (meters, cm, t/m³)
- Area shape: Rectangle
- Length: 4 m
- Width: 3 m
- Depth: 4 cm
- Sand density: 1.3 t/m³
- Bag size: 25 kg
- Extra for compaction and waste: 9%
Find: Sand to order
Answer
2.
Problem 2.
- Units: US (feet, inches, lb/ft³)
- Area shape: Rectangle
- Length: 12 ft
- Width: 12 ft
- Depth: 2 in
- Sand density: 75 lb/ft³
- Bag size: 41 lb
- Extra for compaction and waste: 11%
Find: Sand to order
Answer
3.
Problem 3.
- Units: Metric (meters, cm, t/m³)
- Area shape: Rectangle
- Length: 4 m
- Width: 4 m
- Depth: 4 cm
- Sand density: 2.2 t/m³
- Bag size: 28 kg
- Extra for compaction and waste: 10%
Find: Sand to order
Answer
4.
Problem 4.
- Units: US (feet, inches, lb/ft³)
- Area shape: Rectangle
- Length: 11 ft
- Width: 12 ft
- Depth: 2 in
- Sand density: 100 lb/ft³
- Bag size: 34 lb
- Extra for compaction and waste: 9%
Find: Sand to order
Answer
5.
Problem 5.
- Units: US (feet, inches, lb/ft³)
- Area shape: Circle
- Diameter: 10 ft
- Depth: 1 in
- Sand density: 116 lb/ft³
- Bag size: 60 lb
- Extra for compaction and waste: 7%
Find: Sand to order
Answer
6.
Problem 6.
- Units: Metric (meters, cm, t/m³)
- Area shape: Rectangle
- Length: 4 m
- Width: 3 m
- Depth: 4 cm
- Sand density: 1.6 t/m³
- Bag size: 23 kg
- Extra for compaction and waste: 9%
Find: Sand to order
Answer
7.
Problem 7.
- Units: Metric (meters, cm, t/m³)
- Area shape: Rectangle
- Length: 3 m
- Width: 3 m
- Depth: 5 cm
- Sand density: 1.8 t/m³
- Bag size: 20 kg
- Extra for compaction and waste: 11%
Find: Sand to order
Answer
8.
Problem 8.
- Units: US (feet, inches, lb/ft³)
- Area shape: Circle
- Diameter: 7 ft
- Depth: 2 in
- Sand density: 82 lb/ft³
- Bag size: 54 lb
- Extra for compaction and waste: 12%
Find: Sand to order
Answer
9.
Problem 9.
- Units: Metric (meters, cm, t/m³)
- Area shape: Rectangle
- Length: 3 m
- Width: 3 m
- Depth: 5 cm
- Sand density: 1.3 t/m³
- Bag size: 18 kg
- Extra for compaction and waste: 11%
Find: Sand to order
Answer
10.
Problem 10.
- Units: Metric (meters, cm, t/m³)
- Area shape: Circle
- Diameter: 2.8 m
- Depth: 5 cm
- Sand density: 1.1 t/m³
- Bag size: 20 kg
- Extra for compaction and waste: 12%
Find: Sand to order
Answer

Answer key: Sand worksheet

1. Sand to order: 0.52 m³
1. Find the area: length times width
  $4 \times 3$ $= 12 m²$
2. Find the volume: area times depth. Divide the cm by 100 first, so everything is in meters
  $12 \times \frac{4}{100}$ $= 0.48 m³$
3. Add 9% extra, because sand settles and some gets spilled
  $0.48 \times 1 + 0.09$ $= 0.5232 m³$
4. Find the weight: volume times how much each cubic meter weighs
  $0.5232 \times 1.3$ $= 0.68016 t$
5. Divide the weight in kg by the bag size, and round up so you don't come up short
  $\frac{680.16}{25}$ $= 27.2064$ $= 28 bags$
2. Sand to order: 0.99 yd³
1. Find the area: length times width
  $12 \times 12$ $= 144 ft²$
2. Find the volume: area times depth. Divide the inches by 12 first, so everything is in feet
  $144 \times \frac{2}{12}$ $= 24 ft³$
3. Add 11% extra, because sand settles and some gets spilled
  $24 \times 1 + 0.11$ $= 26.64 ft³$
4. Change to cubic yards, the unit bulk sand is sold in (27 ft³ in 1 yd³)
  $\frac{26.64}{27}$ $= 0.986667 yd³$
5. Find the weight: volume times how much each cubic foot weighs
  $26.64 \times 75$ $= 1,998 lb$
6. Change to US tons (2,000 lb each), since suppliers often sell by the ton
  $\frac{1,998}{2,000}$ $= 0.999 tons$
7. Divide the weight by the bag size, and round up so you don't come up short
  $\frac{1,998}{41}$ $= 48.731707$ $= 49 bags$
3. Sand to order: 0.7 m³
1. Find the area: length times width
  $4 \times 4$ $= 16 m²$
2. Find the volume: area times depth. Divide the cm by 100 first, so everything is in meters
  $16 \times \frac{4}{100}$ $= 0.64 m³$
3. Add 10% extra, because sand settles and some gets spilled
  $0.64 \times 1 + 0.1$ $= 0.704 m³$
4. Find the weight: volume times how much each cubic meter weighs
  $0.704 \times 2.2$ $= 1.5488 t$
5. Divide the weight in kg by the bag size, and round up so you don't come up short
  $\frac{1,548.8}{28}$ $= 55.314286$ $= 56 bags$
4. Sand to order: 0.89 yd³
1. Find the area: length times width
  $11 \times 12$ $= 132 ft²$
2. Find the volume: area times depth. Divide the inches by 12 first, so everything is in feet
  $132 \times \frac{2}{12}$ $= 22 ft³$
3. Add 9% extra, because sand settles and some gets spilled
  $22 \times 1 + 0.09$ $= 23.98 ft³$
4. Change to cubic yards, the unit bulk sand is sold in (27 ft³ in 1 yd³)
  $\frac{23.98}{27}$ $= 0.888148 yd³$
5. Find the weight: volume times how much each cubic foot weighs
  $23.98 \times 100$ $= 2,398 lb$
6. Change to US tons (2,000 lb each), since suppliers often sell by the ton
  $\frac{2,398}{2,000}$ $= 1.199 tons$
7. Divide the weight by the bag size, and round up so you don't come up short
  $\frac{2,398}{34}$ $= 70.529412$ $= 71 bags$
5. Sand to order: 0.26 yd³
1. Find the area of the circle: half the width across, squared, times π (about 3.14)
  $π \times {(\frac{10}{2})}^{2}$ $= 78.539816 ft²$
2. Find the volume: area times depth. Divide the inches by 12 first, so everything is in feet
  $78.539816 \times \frac{1}{12}$ $= 6.544985 ft³$
3. Add 7% extra, because sand settles and some gets spilled
  $6.544985 \times 1 + 0.07$ $= 7.003134 ft³$
4. Change to cubic yards, the unit bulk sand is sold in (27 ft³ in 1 yd³)
  $\frac{7.003134}{27}$ $= 0.259375 yd³$
5. Find the weight: volume times how much each cubic foot weighs
  $7.003134 \times 116$ $= 812.3635 lb$
6. Change to US tons (2,000 lb each), since suppliers often sell by the ton
  $\frac{812.3635}{2,000}$ $= 0.406182 tons$
7. Divide the weight by the bag size, and round up so you don't come up short
  $\frac{812.3635}{60}$ $= 13.539392$ $= 14 bags$
6. Sand to order: 0.52 m³
1. Find the area: length times width
  $4 \times 3$ $= 12 m²$
2. Find the volume: area times depth. Divide the cm by 100 first, so everything is in meters
  $12 \times \frac{4}{100}$ $= 0.48 m³$
3. Add 9% extra, because sand settles and some gets spilled
  $0.48 \times 1 + 0.09$ $= 0.5232 m³$
4. Find the weight: volume times how much each cubic meter weighs
  $0.5232 \times 1.6$ $= 0.83712 t$
5. Divide the weight in kg by the bag size, and round up so you don't come up short
  $\frac{837.12}{23}$ $= 36.396522$ $= 37 bags$
7. Sand to order: 0.5 m³
1. Find the area: length times width
  $3 \times 3$ $= 9 m²$
2. Find the volume: area times depth. Divide the cm by 100 first, so everything is in meters
  $9 \times \frac{5}{100}$ $= 0.45 m³$
3. Add 11% extra, because sand settles and some gets spilled
  $0.45 \times 1 + 0.11$ $= 0.4995 m³$
4. Find the weight: volume times how much each cubic meter weighs
  $0.4995 \times 1.8$ $= 0.8991 t$
5. Divide the weight in kg by the bag size, and round up so you don't come up short
  $\frac{899.1}{20}$ $= 44.955$ $= 45 bags$
8. Sand to order: 0.27 yd³
1. Find the area of the circle: half the width across, squared, times π (about 3.14)
  $π \times {(\frac{7}{2})}^{2}$ $= 38.48451 ft²$
2. Find the volume: area times depth. Divide the inches by 12 first, so everything is in feet
  $38.48451 \times \frac{2}{12}$ $= 6.414085 ft³$
3. Add 12% extra, because sand settles and some gets spilled
  $6.414085 \times 1 + 0.12$ $= 7.183775 ft³$
4. Change to cubic yards, the unit bulk sand is sold in (27 ft³ in 1 yd³)
  $\frac{7.183775}{27}$ $= 0.266066 yd³$
5. Find the weight: volume times how much each cubic foot weighs
  $7.183775 \times 82$ $= 589.069566 lb$
6. Change to US tons (2,000 lb each), since suppliers often sell by the ton
  $\frac{589.069566}{2,000}$ $= 0.294535 tons$
7. Divide the weight by the bag size, and round up so you don't come up short
  $\frac{589.069566}{54}$ $= 10.908696$ $= 11 bags$
9. Sand to order: 0.5 m³
1. Find the area: length times width
  $3 \times 3$ $= 9 m²$
2. Find the volume: area times depth. Divide the cm by 100 first, so everything is in meters
  $9 \times \frac{5}{100}$ $= 0.45 m³$
3. Add 11% extra, because sand settles and some gets spilled
  $0.45 \times 1 + 0.11$ $= 0.4995 m³$
4. Find the weight: volume times how much each cubic meter weighs
  $0.4995 \times 1.3$ $= 0.64935 t$
5. Divide the weight in kg by the bag size, and round up so you don't come up short
  $\frac{649.35}{18}$ $= 36.075$ $= 37 bags$
10. Sand to order: 0.34 m³
1. Find the area of the circle: half the width across, squared, times π (about 3.14)
  $π \times {(\frac{2.8}{2})}^{2}$ $= 6.157522 m²$
2. Find the volume: area times depth. Divide the cm by 100 first, so everything is in meters
  $6.157522 \times \frac{5}{100}$ $= 0.307876 m³$
3. Add 12% extra, because sand settles and some gets spilled
  $0.307876 \times 1 + 0.12$ $= 0.344821 m³$
4. Find the weight: volume times how much each cubic meter weighs
  $0.344821 \times 1.1$ $= 0.379303 t$
5. Divide the weight in kg by the bag size, and round up so you don't come up short
  $\frac{379.303331}{20}$ $= 18.965167$ $= 19 bags$