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Metric Prefix worksheet

Grades 5–6 · CCSS 5.MD.A.1, 5.NBT.A.2

Solve each problem and show your work. Round answers to 2 decimal places where needed.

  1. Problem 1.
    • Value: 3,250
    • From prefix: Milli (m, 10^-3)
    • To prefix: Quetta (Q, 10^30)
    • Unit (optional): A (amperes)

    Find: In quettaA

  2. Problem 2.
    • Value: 2,200
    • From prefix: Pico (p, 10^-12)
    • To prefix: Hecto (h, 10^2)
    • Unit (optional): bit (bits (decimal))

    Find: In hectobit

  3. Problem 3.
    • Value: 2,200
    • From prefix: Tera (T, 10^12)
    • To prefix: Zetta (Z, 10^21)
    • Unit (optional): V (volts)

    Find: In zettaV

  4. Problem 4.
    • Value: 2,700
    • From prefix: Exa (E, 10^18)
    • To prefix: Ronna (R, 10^27)
    • Unit (optional): J (joules)

    Find: In ronnaJ

  5. Problem 5.
    • Value: 2,500
    • From prefix: Micro (µ, 10^-6)
    • To prefix: Deci (d, 10^-1)
    • Unit (optional): Pa (pascals)

    Find: In deciPa

  6. Problem 6.
    • Value: 2,000
    • From prefix: Quecto (q, 10^-30)
    • To prefix: Peta (P, 10^15)
    • Unit (optional): Pa (pascals)

    Find: In petaPa

  7. Problem 7.
    • Value: 1,600
    • From prefix: Zetta (Z, 10^21)
    • To prefix: Pico (p, 10^-12)
    • Unit (optional): Ω (ohms)

    Find: In picoΩ

  8. Problem 8.
    • Value: 2,500
    • From prefix: Zepto (z, 10^-21)
    • To prefix: Peta (P, 10^15)
    • Unit (optional): bit (bits (decimal))

    Find: In petabit

  9. Problem 9.
    • Value: 3,700
    • From prefix: Ronto (r, 10^-27)
    • To prefix: Ronto (r, 10^-27)
    • Unit (optional): H (henries)

    Find: In rontoH

  10. Problem 10.
    • Value: 3,250
    • From prefix: Quetta (Q, 10^30)
    • To prefix: Zepto (z, 10^-21)
    • Unit (optional): Hz (hertz)

    Find: In zeptoHz

Answer key: Metric Prefix worksheet

  1. 1. In quettaA: 3.25e-30 QA

    1. Each prefix is a power of ten: milli is 10^-3 and quetta is 10^30

      1 mA = 10^-3 A; 1 QA = 10^30 A
    2. Subtract the exponents to get the shift: -3 − (30) = -33, so move the decimal point 33 places left

      3,250 mA×10−33=3.25e-30 QA
  2. 2. In hectobit: 2.2e-11 hbit

    1. Each prefix is a power of ten: pico is 10^-12 and hecto is 10^2

      1 pbit = 10^-12 bit; 1 hbit = 10^2 bit
    2. Subtract the exponents to get the shift: -12 − (2) = -14, so move the decimal point 14 places left

      2,200 pbit×10−14=0.000000000022 hbit
  3. 3. In zettaV: 2.2e-6 ZV

    1. Each prefix is a power of ten: tera is 10^12 and zetta is 10^21

      1 TV = 10^12 V; 1 ZV = 10^21 V
    2. Subtract the exponents to get the shift: 12 − (21) = -9, so move the decimal point 9 places left

      2,200 TV×10−9=0.0000022 ZV
  4. 4. In ronnaJ: 2.7e-6 RJ

    1. Each prefix is a power of ten: exa is 10^18 and ronna is 10^27

      1 EJ = 10^18 J; 1 RJ = 10^27 J
    2. Subtract the exponents to get the shift: 18 − (27) = -9, so move the decimal point 9 places left

      2,700 EJ×10−9=0.0000027 RJ
  5. 5. In deciPa: 0.03 dPa

    1. Each prefix is a power of ten: micro is 10^-6 and deci is 10^-1

      1 µPa = 10^-6 Pa; 1 dPa = 10^-1 Pa
    2. Subtract the exponents to get the shift: -6 − (-1) = -5, so move the decimal point 5 places left

      2,500 µPa×10−5=0.025 dPa
  6. 6. In petaPa: 2e-42 PPa

    1. Each prefix is a power of ten: quecto is 10^-30 and peta is 10^15

      1 qPa = 10^-30 Pa; 1 PPa = 10^15 Pa
    2. Subtract the exponents to get the shift: -30 − (15) = -45, so move the decimal point 45 places left

      2,000 qPa×10−45=2e-42 PPa
  7. 7. In picoΩ: 1.6e+36 pΩ

    1. Each prefix is a power of ten: zetta is 10^21 and pico is 10^-12

      1 ZΩ = 10^21 Ω; 1 pΩ = 10^-12 Ω
    2. Subtract the exponents to get the shift: 21 − (-12) = 33, so move the decimal point 33 places right

      1,600 ZΩ×1033=1.6e+36 pΩ
  8. 8. In petabit: 2.5e-33 Pbit

    1. Each prefix is a power of ten: zepto is 10^-21 and peta is 10^15

      1 zbit = 10^-21 bit; 1 Pbit = 10^15 bit
    2. Subtract the exponents to get the shift: -21 − (15) = -36, so move the decimal point 36 places left

      2,500 zbit×10−36=2.5e-33 Pbit
  9. 9. In rontoH: 3,700 rH

    1. Each prefix is a power of ten: ronto is 10^-27 and ronto is 10^-27

      1 rH = 10^-27 H; 1 rH = 10^-27 H
    2. Subtract the exponents to get the shift: -27 − (-27) = 0, so the value doesn't change

      3,700 rH×100=3,700 rH
  10. 10. In zeptoHz: 3.25e+54 zHz

    1. Each prefix is a power of ten: quetta is 10^30 and zepto is 10^-21

      1 QHz = 10^30 Hz; 1 zHz = 10^-21 Hz
    2. Subtract the exponents to get the shift: 30 − (-21) = 51, so move the decimal point 51 places right

      3,250 QHz×1051=3.25e+54 zHz