Smoking Cost worksheet

1. Money saved since quitting: $770.00

1. Find the cost per day: packs a day times the price of a pack

   $1\times \mathrm{\$11.00}$$=\mathrm{\$11.00}$

2. Money not spent: the daily cost times the number of days

   $\mathrm{\$11.00}\times 70$$=\mathrm{\$770.00}$

3. And every year from now on you keep

   $\mathrm{\$11.00}\times 365$$=\mathrm{\$4,015.00}$

2. Cost over 11 years: $39,380.15

1. Find the cost per day: packs a day times the price of a pack

   $1\times \mathrm{\$8.00}$$=\mathrm{\$8.00}$

2. Multiply the daily cost by 365 days to get a year at today's price

   $\mathrm{\$8.00}\times 365$$=\mathrm{\$2,920.00}$

3. Add up 11 years with the price rising 4% a year (g is that rise as a decimal), each year costing a bit more

   $\mathrm{\$2,920.00}\times \frac{{\left(1+0.04\right)}^{11}-1}{0.04}$$=\mathrm{\$39,380.15}$

4. If invested instead: each year's cost goes in at year end and grows at 4% until year 11

   $\mathrm{\Sigma \; cost\; in\; year\; y\; \times \; 1.04^(11\; -\; y)}$$=\mathrm{\$47,545.45}$

3. Cost over 14 years: $78,688.51

1. Find the cost per day: packs a day times the price of a pack

   $1\times \mathrm{\$11.00}$$=\mathrm{\$11.00}$

2. Multiply the daily cost by 365 days to get a year at today's price

   $\mathrm{\$11.00}\times 365$$=\mathrm{\$4,015.00}$

3. Add up 14 years with the price rising 5% a year (g is that rise as a decimal), each year costing a bit more

   $\mathrm{\$4,015.00}\times \frac{{\left(1+0.05\right)}^{14}-1}{0.05}$$=\mathrm{\$78,688.51}$

4. If invested instead: each year's cost goes in at year end and grows at 5% until year 14

   $\mathrm{\Sigma \; cost\; in\; year\; y\; \times \; 1.05^(14\; -\; y)}$$=\mathrm{\$105,992.34}$

4. Money saved since quitting: $686.00

1. Find the cost per day: packs a day times the price of a pack

   $1\times \mathrm{\$7.00}$$=\mathrm{\$7.00}$

2. Money not spent: the daily cost times the number of days

   $\mathrm{\$7.00}\times 98$$=\mathrm{\$686.00}$

3. And every year from now on you keep

   $\mathrm{\$7.00}\times 365$$=\mathrm{\$2,555.00}$

5. Money saved since quitting: $525.00

1. Find the cost per day: packs a day times the price of a pack

   $1\times \mathrm{\$7.00}$$=\mathrm{\$7.00}$

2. Money not spent: the daily cost times the number of days

   $\mathrm{\$7.00}\times 75$$=\mathrm{\$525.00}$

3. And every year from now on you keep

   $\mathrm{\$7.00}\times 365$$=\mathrm{\$2,555.00}$

6. Cost over 12 years: $27,422.09

1. Find the cost per day: packs a day times the price of a pack

   $1\times \mathrm{\$5.00}$$=\mathrm{\$5.00}$

2. Multiply the daily cost by 365 days to get a year at today's price

   $\mathrm{\$5.00}\times 365$$=\mathrm{\$1,825.00}$

3. Add up 12 years with the price rising 4% a year (g is that rise as a decimal), each year costing a bit more

   $\mathrm{\$1,825.00}\times \frac{{\left(1+0.04\right)}^{12}-1}{0.04}$$=\mathrm{\$27,422.09}$

4. If invested instead: each year's cost goes in at year end and grows at 3% until year 12

   $\mathrm{\Sigma \; cost\; in\; year\; y\; \times \; 1.03^(12\; -\; y)}$$=\mathrm{\$31,987.02}$

7. Money saved since quitting: $770.00

1. Find the cost per day: packs a day times the price of a pack

   $1\times \mathrm{\$7.00}$$=\mathrm{\$7.00}$

2. Money not spent: the daily cost times the number of days

   $\mathrm{\$7.00}\times 110$$=\mathrm{\$770.00}$

3. And every year from now on you keep

   $\mathrm{\$7.00}\times 365$$=\mathrm{\$2,555.00}$

8. Cost over 10 years: $39,966.48

1. Find the cost per day: packs a day times the price of a pack

   $1\times \mathrm{\$10.00}$$=\mathrm{\$10.00}$

2. Multiply the daily cost by 365 days to get a year at today's price

   $\mathrm{\$10.00}\times 365$$=\mathrm{\$3,650.00}$

3. Add up 10 years with the price rising 2% a year (g is that rise as a decimal), each year costing a bit more

   $\mathrm{\$3,650.00}\times \frac{{\left(1+0.02\right)}^{10}-1}{0.02}$$=\mathrm{\$39,966.48}$

4. If invested instead: each year's cost goes in at year end and grows at 4% until year 10

   $\mathrm{\Sigma \; cost\; in\; year\; y\; \times \; 1.04^(10\; -\; y)}$$=\mathrm{\$47,678.10}$

9. Money saved since quitting: $760.00

1. Find the cost per day: packs a day times the price of a pack

   $1\times \mathrm{\$8.00}$$=\mathrm{\$8.00}$

2. Money not spent: the daily cost times the number of days

   $\mathrm{\$8.00}\times 95$$=\mathrm{\$760.00}$

3. And every year from now on you keep

   $\mathrm{\$8.00}\times 365$$=\mathrm{\$2,920.00}$

10. Money saved since quitting: $840.00

1. Find the cost per day: packs a day times the price of a pack

   $1\times \mathrm{\$8.00}$$=\mathrm{\$8.00}$

2. Money not spent: the daily cost times the number of days

   $\mathrm{\$8.00}\times 105$$=\mathrm{\$840.00}$

3. And every year from now on you keep

   $\mathrm{\$8.00}\times 365$$=\mathrm{\$2,920.00}$