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Surface Area worksheet

Grades 6–8 · CCSS 6.G.A.4, 7.G.B.6

Solve each problem and show your work. Round answers to 2 decimal places where needed.

  1. Problem 1.
    • Shape: Sphere
    • Measurement unit: Millimeters (mm)
    • Radius: 2

    Find: Total surface area

  2. Problem 2.
    • Shape: Sphere
    • Measurement unit: Feet (ft)
    • Radius: 1.8

    Find: Total surface area

  3. Problem 3.
    • Shape: Rectangular box (cuboid)
    • Measurement unit: Meters (m)
    • Length: 3
    • Width: 3
    • Height: 2

    Find: Total surface area

  4. Problem 4.
    • Shape: Cube
    • Measurement unit: Centimeters (cm)
    • Edge length: 3

    Find: Total surface area

  5. Problem 5.
    • Shape: Cone
    • Measurement unit: Meters (m)
    • Radius: 1.8
    • Height: 2

    Find: Total surface area

  6. Problem 6.
    • Shape: Rectangular box (cuboid)
    • Measurement unit: Feet (ft)
    • Length: 3
    • Width: 3
    • Height: 2

    Find: Total surface area

  7. Problem 7.
    • Shape: Rectangular pyramid
    • Measurement unit: Yards (yd)
    • Length: 6
    • Width: 3
    • Height: 3

    Find: Total surface area

  8. Problem 8.
    • Shape: Rectangular box (cuboid)
    • Measurement unit: Feet (ft)
    • Length: 5
    • Width: 2
    • Height: 2

    Find: Total surface area

  9. Problem 9.
    • Shape: Cone
    • Measurement unit: Yards (yd)
    • Radius: 1.1
    • Height: 2

    Find: Total surface area

  10. Problem 10.
    • Shape: Cube
    • Measurement unit: Millimeters (mm)
    • Edge length: 1

    Find: Total surface area

Answer key: Surface Area worksheet

  1. 1. Total surface area: 50.27 mm²

    1. A sphere's surface equals four circles of the same radius: 4 × π × r²

      4×π×22=50.265482 mm²
    2. To convert to square meters, multiply by (1 mm in meters)²

      50.265482 mm²×0.0012=0.00005 m²
  2. 2. Total surface area: 40.72 ft²

    1. A sphere's surface equals four circles of the same radius: 4 × π × r²

      4×π×1.82=40.715041 ft²
    2. To convert to square meters, multiply by (1 ft in meters)²

      40.715041 ft²×0.30482=3.782551 m²
  3. 3. Total surface area: 42 m²

    1. A box has three pairs of matching rectangles, so add one of each and double it

      2×(3×3+3×2+3×2)=2×(9+6+6)=42 m²
  4. 4. Total surface area: 54 cm²

    1. A cube has six matching square faces, so multiply the area of one face (edge²) by 6

      6×32=54 cm²
    2. To convert to square meters, multiply by (1 cm in meters)²

      54 cm²×0.012=0.0054 m²
  5. 5. Total surface area: 25.39 m²

    1. Find the slant height (l), the length along the sloping side, with the Pythagorean theorem

      l=1.82+22=2.690725
    2. Curved surface: π times the radius times the slant height

      π×1.8×2.690725=15.21569 m²
    3. Circular base: π times the radius squared

      π×1.82=10.17876 m²
    4. Total: curved surface plus base

      15.21569+10.17876=25.394451 m²
  6. 6. Total surface area: 42 ft²

    1. A box has three pairs of matching rectangles, so add one of each and double it

      2×(3×3+3×2+3×2)=2×(9+6+6)=42 ft²
    2. To convert to square meters, multiply by (1 ft in meters)²

      42 ft²×0.30482=3.901928 m²
  7. 7. Total surface area: 50.85 yd²

    1. Find the slant height of the two faces on the length edges, using the height and half the width

      32+(32)2=3.354102
    2. Find the slant height of the two faces on the width edges, using the height and half the length

      32+(62)2=4.242641
    3. Add the four triangles, in two pairs. Each triangle is half its base edge times its slant height

      6×3.354102+3×4.242641=32.852534 yd²
    4. Total: the triangular faces plus the rectangular base (l × w)

      32.852534+6×3=50.852534 yd²
    5. To convert to square meters, multiply by (1 yd in meters)²

      50.852534 yd²×0.91442=42.519195 m²
  8. 8. Total surface area: 48 ft²

    1. A box has three pairs of matching rectangles, so add one of each and double it

      2×(5×2+5×2+2×2)=2×(10+10+4)=48 ft²
    2. To convert to square meters, multiply by (1 ft in meters)²

      48 ft²×0.30482=4.459346 m²
  9. 9. Total surface area: 11.69 yd²

    1. Find the slant height (l), the length along the sloping side, with the Pythagorean theorem

      l=1.12+22=2.282542
    2. Curved surface: π times the radius times the slant height

      π×1.1×2.282542=7.8879 yd²
    3. Circular base: π times the radius squared

      π×1.12=3.801327 yd²
    4. Total: curved surface plus base

      7.8879+3.801327=11.689228 yd²
    5. To convert to square meters, multiply by (1 yd in meters)²

      11.689228 yd²×0.91442=9.773683 m²
  10. 10. Total surface area: 6 mm²

    1. A cube has six matching square faces, so multiply the area of one face (edge²) by 6

      6×12=6 mm²
    2. To convert to square meters, multiply by (1 mm in meters)²

      6 mm²×0.0012=0.000006 m²