Printable worksheet

← Back to the Unix Timestamp Converter

In the print window, choose “Save as PDF” as the printer (or print it on paper). Seed 1 rebuilds this exact sheet.

Unix Timestamp worksheet

Grades 5–6 · CCSS 5.MD.A.1

Solve each problem and show your work. Round answers to 2 decimal places where needed.

1.
Problem 1.
- Convert: Date to timestamp
- Date (UTC): Feb 6, 2026
- Time (UTC, 24-hour): 16:49
- Seconds: 0
- Also show in time zone: UTC only
Find: Unix timestamp (seconds)
Answer
2.
Problem 2.
- Convert: Timestamp to date
- Unix timestamp: 2,200,000,000 seconds
- Also show in time zone: Moscow
Find: Date and time (UTC)
Answer
3.
Problem 3.
- Convert: Timestamp to date
- Unix timestamp: 1,400,000,000 seconds
- Also show in time zone: Los Angeles (US Pacific)
Find: Date and time (UTC)
Answer
4.
Problem 4.
- Convert: Timestamp to date
- Unix timestamp: 1,650,000,000 seconds
- Also show in time zone: São Paulo
Find: Date and time (UTC)
Answer
5.
Problem 5.
- Convert: Timestamp to date
- Unix timestamp: 1,600,000,000 seconds
- Also show in time zone: Moscow
Find: Date and time (UTC)
Answer
6.
Problem 6.
- Convert: Date to timestamp
- Date (UTC): May 14, 2025
- Time (UTC, 24-hour): 14:13
- Seconds: 0
- Also show in time zone: India (Kolkata)
Find: Unix timestamp (seconds)
Answer
7.
Problem 7.
- Convert: Date to timestamp
- Date (UTC): Jun 20, 2025
- Time (UTC, 24-hour): 14:34
- Seconds: 1
- Also show in time zone: Auckland
Find: Unix timestamp (seconds)
Answer
8.
Problem 8.
- Convert: Timestamp to date
- Unix timestamp: 1,750,000,000 seconds
- Also show in time zone: Chicago (US Central)
Find: Date and time (UTC)
Answer
9.
Problem 9.
- Convert: Timestamp to date
- Unix timestamp: 2,000,000,000 seconds
- Also show in time zone: UTC only
Find: Date and time (UTC)
Answer
10.
Problem 10.
- Convert: Date to timestamp
- Date (UTC): Aug 10, 2025
- Time (UTC, 24-hour): 13:46
- Seconds: 0
- Also show in time zone: São Paulo
Find: Unix timestamp (seconds)
Answer

Answer key: Unix Timestamp worksheet

1. Unix timestamp (seconds): 1770396540
1. Count the days from January 1, 1970, the starting point of Unix time, to Feb 6, 2026 (negative for earlier dates)
  $days since the epoch$ $= 20,490$
2. Turn everything into seconds: each day is 86,400 seconds, each hour 3,600 and each minute 60. Then add them up
  $20,490 \times 86,400 + 16 \times 3,600 + 49 \times 60 + 0$ $= 1,770,396,540$
3. Write it without commas, the way computers store it
  $Unix time$ $= 1770396540$
2. Date and time (UTC): Sun, Sep 18, 2039 23:06:40 UTC
1. Find the whole days since January 1, 1970: divide by the 86,400 seconds in a day and round down
  $⌊ \frac{2,200,000,000}{86,400} ⌋$ $= 25,462$
2. The seconds left over tell you how far into that day it is, in UTC
  $2,200,000,000 - 25,462 \times 86,400$ $= 83,200 s$
3. Split those leftover seconds into hours (3,600 seconds each), minutes (60 seconds each) and seconds
  $83,200 s$ $= 23:06:40$
4. Count 25,462 days forward from Thursday, January 1, 1970 to find the date
  $Jan 1, 1970 + 25,462 days$ $= Sun, Sep 18, 2039$
5. Put the date and time together
  $UTC$ $= Sun, Sep 18, 2039 23:06:40 UTC$
3. Date and time (UTC): Tue, May 13, 2014 16:53:20 UTC
1. Find the whole days since January 1, 1970: divide by the 86,400 seconds in a day and round down
  $⌊ \frac{1,400,000,000}{86,400} ⌋$ $= 16,203$
2. The seconds left over tell you how far into that day it is, in UTC
  $1,400,000,000 - 16,203 \times 86,400$ $= 60,800 s$
3. Split those leftover seconds into hours (3,600 seconds each), minutes (60 seconds each) and seconds
  $60,800 s$ $= 16:53:20$
4. Count 16,203 days forward from Thursday, January 1, 1970 to find the date
  $Jan 1, 1970 + 16,203 days$ $= Tue, May 13, 2014$
5. Put the date and time together
  $UTC$ $= Tue, May 13, 2014 16:53:20 UTC$
4. Date and time (UTC): Fri, Apr 15, 2022 05:20:00 UTC
1. Find the whole days since January 1, 1970: divide by the 86,400 seconds in a day and round down
  $⌊ \frac{1,650,000,000}{86,400} ⌋$ $= 19,097$
2. The seconds left over tell you how far into that day it is, in UTC
  $1,650,000,000 - 19,097 \times 86,400$ $= 19,200 s$
3. Split those leftover seconds into hours (3,600 seconds each), minutes (60 seconds each) and seconds
  $19,200 s$ $= 05:20:00$
4. Count 19,097 days forward from Thursday, January 1, 1970 to find the date
  $Jan 1, 1970 + 19,097 days$ $= Fri, Apr 15, 2022$
5. Put the date and time together
  $UTC$ $= Fri, Apr 15, 2022 05:20:00 UTC$
5. Date and time (UTC): Sun, Sep 13, 2020 12:26:40 UTC
1. Find the whole days since January 1, 1970: divide by the 86,400 seconds in a day and round down
  $⌊ \frac{1,600,000,000}{86,400} ⌋$ $= 18,518$
2. The seconds left over tell you how far into that day it is, in UTC
  $1,600,000,000 - 18,518 \times 86,400$ $= 44,800 s$
3. Split those leftover seconds into hours (3,600 seconds each), minutes (60 seconds each) and seconds
  $44,800 s$ $= 12:26:40$
4. Count 18,518 days forward from Thursday, January 1, 1970 to find the date
  $Jan 1, 1970 + 18,518 days$ $= Sun, Sep 13, 2020$
5. Put the date and time together
  $UTC$ $= Sun, Sep 13, 2020 12:26:40 UTC$
6. Unix timestamp (seconds): 1747231980
1. Count the days from January 1, 1970, the starting point of Unix time, to May 14, 2025 (negative for earlier dates)
  $days since the epoch$ $= 20,222$
2. Turn everything into seconds: each day is 86,400 seconds, each hour 3,600 and each minute 60. Then add them up
  $20,222 \times 86,400 + 14 \times 3,600 + 13 \times 60 + 0$ $= 1,747,231,980$
3. Write it without commas, the way computers store it
  $Unix time$ $= 1747231980$
7. Unix timestamp (seconds): 1750430041
1. Count the days from January 1, 1970, the starting point of Unix time, to Jun 20, 2025 (negative for earlier dates)
  $days since the epoch$ $= 20,259$
2. Turn everything into seconds: each day is 86,400 seconds, each hour 3,600 and each minute 60. Then add them up
  $20,259 \times 86,400 + 14 \times 3,600 + 34 \times 60 + 1$ $= 1,750,430,041$
3. Write it without commas, the way computers store it
  $Unix time$ $= 1750430041$
8. Date and time (UTC): Sun, Jun 15, 2025 15:06:40 UTC
1. Find the whole days since January 1, 1970: divide by the 86,400 seconds in a day and round down
  $⌊ \frac{1,750,000,000}{86,400} ⌋$ $= 20,254$
2. The seconds left over tell you how far into that day it is, in UTC
  $1,750,000,000 - 20,254 \times 86,400$ $= 54,400 s$
3. Split those leftover seconds into hours (3,600 seconds each), minutes (60 seconds each) and seconds
  $54,400 s$ $= 15:06:40$
4. Count 20,254 days forward from Thursday, January 1, 1970 to find the date
  $Jan 1, 1970 + 20,254 days$ $= Sun, Jun 15, 2025$
5. Put the date and time together
  $UTC$ $= Sun, Jun 15, 2025 15:06:40 UTC$
9. Date and time (UTC): Wed, May 18, 2033 03:33:20 UTC
1. Find the whole days since January 1, 1970: divide by the 86,400 seconds in a day and round down
  $⌊ \frac{2,000,000,000}{86,400} ⌋$ $= 23,148$
2. The seconds left over tell you how far into that day it is, in UTC
  $2,000,000,000 - 23,148 \times 86,400$ $= 12,800 s$
3. Split those leftover seconds into hours (3,600 seconds each), minutes (60 seconds each) and seconds
  $12,800 s$ $= 03:33:20$
4. Count 23,148 days forward from Thursday, January 1, 1970 to find the date
  $Jan 1, 1970 + 23,148 days$ $= Wed, May 18, 2033$
5. Put the date and time together
  $UTC$ $= Wed, May 18, 2033 03:33:20 UTC$
10. Unix timestamp (seconds): 1754833560
1. Count the days from January 1, 1970, the starting point of Unix time, to Aug 10, 2025 (negative for earlier dates)
  $days since the epoch$ $= 20,310$
2. Turn everything into seconds: each day is 86,400 seconds, each hour 3,600 and each minute 60. Then add them up
  $20,310 \times 86,400 + 13 \times 3,600 + 46 \times 60 + 0$ $= 1,754,833,560$
3. Write it without commas, the way computers store it
  $Unix time$ $= 1754833560$