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Voltage Divider worksheet

Grades 11–12 · CCSS HSA.CED.A.4

Solve each problem and show your work. Round answers to 2 decimal places where needed.

1.
Problem 1.
- Solve for: R1 (top)
- Input voltage (Vin): 12 V
- Target output voltage (Vout): 5 V
- R2, between the output and ground: 5,600 Ω
Find: R1 (top)
Answer
2.
Problem 2.
- Solve for: R1 (top)
- Input voltage (Vin): 10 V
- Target output voltage (Vout): 5 V
- R2, between the output and ground: 4,000 Ω
Find: R1 (top)
Answer
3.
Problem 3.
- Solve for: Output voltage
- Input voltage (Vin): 12 V
- R1, between Vin and the output: 10,000 Ω
- R2, between the output and ground: 5,600 Ω
Find: Output voltage
Answer
4.
Problem 4.
- Solve for: Output voltage
- Input voltage (Vin): 9 V
- R1, between Vin and the output: 8,200 Ω
- R2, between the output and ground: 5,000 Ω
Find: Output voltage
Answer
5.
Problem 5.
- Solve for: R2 (bottom)
- Input voltage (Vin): 12 V
- Target output voltage (Vout): 7 V
- R1, between Vin and the output: 9,000 Ω
Find: R2 (bottom)
Answer
6.
Problem 6.
- Solve for: Output voltage
- Input voltage (Vin): 16 V
- R1, between Vin and the output: 11,250 Ω
- R2, between the output and ground: 4,800 Ω
Find: Output voltage
Answer
7.
Problem 7.
- Solve for: R1 (top)
- Input voltage (Vin): 12 V
- Target output voltage (Vout): 5 V
- R2, between the output and ground: 4,500 Ω
Find: R1 (top)
Answer
8.
Problem 8.
- Solve for: Output voltage
- Input voltage (Vin): 12 V
- R1, between Vin and the output: 6,500 Ω
- R2, between the output and ground: 4,250 Ω
Find: Output voltage
Answer
9.
Problem 9.
- Solve for: Output voltage
- Input voltage (Vin): 15 V
- R1, between Vin and the output: 8,600 Ω
- R2, between the output and ground: 5,500 Ω
Find: Output voltage
Answer
10.
Problem 10.
- Solve for: Output voltage
- Input voltage (Vin): 14 V
- R1, between Vin and the output: 6,500 Ω
- R2, between the output and ground: 5,000 Ω
Find: Output voltage
Answer

Answer key: Voltage Divider worksheet

1. R1 (top): 7,840 Ω
1. Find the top resistor R1 by rearranging the divider formula: R1 = R2 × (Vin − Vout) ÷ Vout
  $R1$ $= \frac{5,600 \times 12 - 5}{5}$ $= 7,840 Ω$
2. Find the current drawn from the source: the input voltage ÷ the total resistance (Ohm's law)
  $I$ $= \frac{12}{7,840 + 5,600}$ $= 0.0008928571 A$
2. R1 (top): 4,000 Ω
1. Find the top resistor R1 by rearranging the divider formula: R1 = R2 × (Vin − Vout) ÷ Vout
  $R1$ $= \frac{4,000 \times 10 - 5}{5}$ $= 4,000 Ω$
2. Find the current drawn from the source: the input voltage ÷ the total resistance (Ohm's law)
  $I$ $= \frac{10}{4,000 + 4,000}$ $= 0.00125 A$
3. Output voltage: 4.31 V
1. Find the output voltage. It's the input times the bottom resistor's share of the total: Vout = Vin × R2 ÷ (R1 + R2)
  $Vout$ $= \frac{12 \times 5,600}{10,000 + 5,600}$ $= 4.3076923077 V$
2. Find the current drawn from the source: the input voltage ÷ the total resistance (Ohm's law)
  $I$ $= \frac{12}{10,000 + 5,600}$ $= 0.0007692308 A$
4. Output voltage: 3.41 V
1. Find the output voltage. It's the input times the bottom resistor's share of the total: Vout = Vin × R2 ÷ (R1 + R2)
  $Vout$ $= \frac{9 \times 5,000}{8,200 + 5,000}$ $= 3.4090909091 V$
2. Find the current drawn from the source: the input voltage ÷ the total resistance (Ohm's law)
  $I$ $= \frac{9}{8,200 + 5,000}$ $= 0.0006818182 A$
5. R2 (bottom): 12,600 Ω
1. Find the bottom resistance you need by rearranging the divider formula: R2 = R1 × Vout ÷ (Vin − Vout)
  $R2$ $= \frac{9,000 \times 7}{12 - 7}$ $= 12,600 Ω$
2. Find the current drawn from the source: the input voltage ÷ the total resistance (Ohm's law)
  $I$ $= \frac{12}{9,000 + 12,600}$ $= 0.0005555556 A$
6. Output voltage: 4.79 V
1. Find the output voltage. It's the input times the bottom resistor's share of the total: Vout = Vin × R2 ÷ (R1 + R2)
  $Vout$ $= \frac{16 \times 4,800}{11,250 + 4,800}$ $= 4.785046729 V$
2. Find the current drawn from the source: the input voltage ÷ the total resistance (Ohm's law)
  $I$ $= \frac{16}{11,250 + 4,800}$ $= 0.0009968847 A$
7. R1 (top): 6,300 Ω
1. Find the top resistor R1 by rearranging the divider formula: R1 = R2 × (Vin − Vout) ÷ Vout
  $R1$ $= \frac{4,500 \times 12 - 5}{5}$ $= 6,300 Ω$
2. Find the current drawn from the source: the input voltage ÷ the total resistance (Ohm's law)
  $I$ $= \frac{12}{6,300 + 4,500}$ $= 0.0011111111 A$
8. Output voltage: 4.74 V
1. Find the output voltage. It's the input times the bottom resistor's share of the total: Vout = Vin × R2 ÷ (R1 + R2)
  $Vout$ $= \frac{12 \times 4,250}{6,500 + 4,250}$ $= 4.7441860465 V$
2. Find the current drawn from the source: the input voltage ÷ the total resistance (Ohm's law)
  $I$ $= \frac{12}{6,500 + 4,250}$ $= 0.0011162791 A$
9. Output voltage: 5.85 V
1. Find the output voltage. It's the input times the bottom resistor's share of the total: Vout = Vin × R2 ÷ (R1 + R2)
  $Vout$ $= \frac{15 \times 5,500}{8,600 + 5,500}$ $= 5.8510638298 V$
2. Find the current drawn from the source: the input voltage ÷ the total resistance (Ohm's law)
  $I$ $= \frac{15}{8,600 + 5,500}$ $= 0.0010638298 A$
10. Output voltage: 6.09 V
1. Find the output voltage. It's the input times the bottom resistor's share of the total: Vout = Vin × R2 ÷ (R1 + R2)
  $Vout$ $= \frac{14 \times 5,000}{6,500 + 5,000}$ $= 6.0869565217 V$
2. Find the current drawn from the source: the input voltage ÷ the total resistance (Ohm's law)
  $I$ $= \frac{14}{6,500 + 5,000}$ $= 0.0012173913 A$